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EastWind [94]
3 years ago
14

Write the equation of the line that is perpendicular to the line 5y=x−5 through the point (-1,0).

Mathematics
1 answer:
uranmaximum [27]3 years ago
7 0

Steps:

---> Re arrange equation to get the format: y = mx + c

---> Work out the perpendicular gradient from the first equation

----> Substitute the x and y coordinates of point (-1, 0) and the perpendicular      gradient into y = mx + c   and work out c

---> Finally, substitute the perpendicular gradient and the value for c into y =mx + c  to get the gradient of the perpendicular line:

__________________________________________

Rearranging equation into the format: y = mx + c:

5y = x - 5                  <em>(Just divide both sides by y)</em>

y = \frac{1}{5}x -1

___________________________________________

Working out the perpendicular gradient:

To work out the perpendicular gradient, we just take the negative reciprocal of the gradient of y = \frac{1}{5}x -1

<em>Note: negative reciprocal means we just flip the fraction and put a minus sign.</em>

The regular gradient is: \frac{1}{5}

So the perpendicular gradient is the negative reciprocal of \frac{1}{5}

which is -5       <em> (note: \frac{-5}{1} is just 5-)</em>

<em>___________________________________________</em>

Now lets substitute in the values for the gradient (m), the y coord (0) and x coord (-1) of the point (-1, 0)   into y = mx + c, and solve for c:

y = mx + c     <em>(substitute in all known values)</em>

0 = -5(-1) + c   <em> (the -1 times -5 will make + 5)</em>

0 = 5 + c        <em>(subtract 5 from both sides to cancel out the + 5)</em>

-5 = c

so c = -5

____________________________________________

Finally, just substitute in the perpendicular gradient and the value for c into y = mx + c   to get the equation of the perpendicular line:

y = mx + c        <em>(substitute in the perp. gradient and c)</em>

y = -5x - 5

____________________________________________________

<h2>Answer:</h2>

The equation to the line perpendicular to 5y = x - 5 through point (-1, 0) is :

C. y = -5x - 5

_______________________________________________

A quicker way to get equation of the perpendicular line once you know the perp. gradient is to use the equation:

y - y1 = m (x - x1)

y1 is the y coordinate of (-1, 0)

x1 is the x coordinate of (-1, 0)

m is the perpendicular gradient.

y - y1 = m (x - x1)       <em>(Substitute in values)</em>

y - 0 = -5 ( x - - 1)       <em>(simplify)</em>

y = -5 (x + 1)              <em>(expand the brackets)</em>

y = -5x - 5

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