Answer:
86
Step-by-step explanation:
In this question, we are asked to calculate the average mean score for a group of students split into two different emerging groups.
We calculate the total score for each of the groups. This is done by multiplying the average score by the number of students.
Total score of section A is 15 * 80 = 1,200
For section B, total score is 20 * 90 = 1,800
Overall score is thus 1200 + 1800 = 3000
We add the scores together and divide by the total number of students in both sections
Average score is thus 3000/35 = 85.71 which is approximately 86
Answer:
A and B
Step-by-step explanation:
Each side in Chloe's triangle is 1.5 times the length of each side in Juan's triangle. Thus, they are 'similar' by the <u>math </u>definition of that word, by the SSS Rule for Similar Triangles.
That means they are different only in size. So, their angle measures are the same and they are the same shape.
A and B are true.
C is never true, because the sum of all 3 angles in a triangle is always 180°.
D is not true, because they are similar.
18
First you want to change the 20% into a decimal which is .20
Next you want to multiply 90 by .20 because that will give you the answer for 20% of 90
90x.20=18
Hope that helps
Answer:
x= 4 y= 7 z= -6
Step-by-step explanation:
solve for one and you get them all
First, I got rid of the z by multiplying common factors (multiplied z by 2) and added equations 2 and 3 together after multiplying by 2
4x - 3y - 2z = 7
-10x+10y+2z= 18
-6x+7y= 25
Then multiplied z by -3 (to get rid of the z) with the original equation 3
3x - 2y + 3z = -20
15x-15y-3z= -27
18x-17y= -47
Next find common thing between the 2 equations we got and multiply it by that and combine (we can multiply first equation by 3 to get rid of the x and solve for y)
-18x+21y= 75
18x-17y= -47
y=7
Work backwards, substitute 7 into the above equation, you get x= 4 and then same for z to get z= -6
Answer:
b. (1, 3, -2)
Step-by-step explanation:
A graphing calculator or scientific calculator can solve this system of equations for you, or you can use any of the usual methods: elimination, substitution, matrix methods, Cramer's rule.
It can also work well to try the offered choices in the given equations. Sometimes, it can work best to choose an equation other than the first one for this. The last equation here seems a good one for eliminating bad answers:
a: -1 -5(1) +2(-4) = -14 ≠ -18
b: 1 -5(3) +2(-2) = -18 . . . . potential choice
c: 3 -5(8) +2(1) = -35 ≠ -18
d: 2 -5(-3) +2(0) = 17 ≠ -18
This shows choice B as the only viable option. Further checking can be done to make sure that solution works in the other equations:
2(1) +(3) -3(-2) = 11 . . . . choice B works in equation 1
-(1) +2(3) +4(-2) = -3 . . . choice B works in equation 2
