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Lelechka [254]
3 years ago
5

You lay a ladder against a building window. The building makes a right angle to the ground. The building is 30 feet tall, and th

e distance from the bottom of the building to the bottom of the ladder is 12 feet. What is the distance from the bottom of the ladder to the window?

Mathematics
1 answer:
damaskus [11]3 years ago
8 0

Answer:

32.3 feet.

Step-by-step explanation:

I attached a picture to show u the work!! sorry I spelled pythagorean theorem

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A homeowner's electric bill for the month was $155.80 for 1,900 kilowatt-hours of
sergij07 [2.7K]
I’m almost done solving this
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3 years ago
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blondinia [14]

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4 0
4 years ago
The length of a rectangle is triple the width. If the area of the rectangle is 75 square inches, then find the length and width
Ronch [10]

Answer:

W = 5

L = 15

Step-by-step explanation:

Formula for Area of Rectangle is L × W

Since stated triple;

L = 3W

Area = L×W = 3W² = 75

It'll be:

3W² = 75

Divide both sides with 3:

<u>3</u><u>W</u><u>²</u> = <u>7</u><u>5</u>

3 3

W² = 25

Then square root both sides:

w = 5

Again stated that length is triple the width:

L = 5 × 3

L = 15

Therefore;

W = 5

L = 15

5 0
2 years ago
The length of a leg of an isosceles right triangle is 20 inches. Find the length of the hypotenuse in radical form
Over [174]

Answer: H = 20\sqrt{2}

Step-by-step explanation:

To find the hypotenuse , we will use Pythagoras theorem, which states that

The square of the hypotenuse = the square of the adjacent + the square of the opposite.

Since , we are dealing with isosceles right triangle , this means that :

both the adjacent and the opposite are equal, using the formula to find the hypotenuse , let H represent the hypotenuse , then

H^{2} = 20^{2} +  20^{2}

H^{2} = 400 + 400

H^{2} = 800

Take the square root of both sides

H = \sqrt{800}

\sqrt{800} can be written as \sqrt{400} x\sqrt{2}

Therefore :

H = \sqrt{400} x\sqrt{2}

H = 20x \sqrt{2}

H = 20\sqrt{2}

6 0
3 years ago
7, 9, 13 are the first three terms of a sequence with
ivann1987 [24]

(i) The simultaneous equations in a, b and c are a+b+c = 7 , 4a+2b+c = 9 & 9a+3b+c = 13  

(ii) Expression for nth term = n²-n+7

The first three terms of the sequence are 7, 9, 13

nth term = an²+bn+c

If we put n = 1 then,

1st term = a(1)²+b+c

⇒ a+b+c = 7   ......(1)

If we put n = 2 then,

2nd term = a(2)²+b×2+c

⇒ 4a+2b+c = 9    ........(2)

3rd term = a(3)²+b×3+c

⇒ 9a+3b+c = 13   .......(3)

Multiplying 4 with (1) and subtract (2) from (1) we get,

(4a+4b+4c)-(4a+2b+c)=28-9

⇒ 4a+4b+4c-4a-2b-c=19

⇒ 2b+3c=19 .....(4)

Multiplying 9 with (1) and subtract (3) from (1) we get,

(9a+9b+9c)-(9a+3b+c)=63-13

⇒ 9a+9b+9c-9a-3b-c=50

⇒ 6b+8c=50

⇒ 3b+4c=25 .....(5)

Multiplying 3 with (4) and multiplying 2 with (5), then subtract (5) from (4),

3(2b+3c)-2(3b+4c)=57-50

⇒ 6b+9c-6b-8c=7

⇒ c = 7

From (5),

3b+28 = 25

⇒ 3b = -3

⇒ b = -1

From (1),

a+(-1)+7 = 7

⇒ a-1=0

⇒ a=1

So, nth term = n²-n+7

Learn more about sequence here :

brainly.com/question/6561461

#SPJ10

8 0
2 years ago
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