2((x+2)(x+2)}-4=28
2{x^2 + 4x + 4}-4=28
2x^2 +4x=28
2(x^2+2x)=28
x^2+2x=28/2
x^2+2x=14
A linear equation of the form :
y = mx+b
can have at the most ONE x-intercept and at the most ONE y-intercept
I can conclude that this linear equation DOESN'T pass through the origin (O) and that it intercepts the x-axis as well as the y-axis
Answer: T = 4
Step-by-step explanation:
1. Write all the variables down
P = 8 V = 2X N = 2 R = 2X X = 3
2. Since you know that X = 3 substitute it in to find V and R
V = 2X = 2(3) = 6
R = 2X = 2(3) = 6
3. Find PV
PV = P x V
= 8 x 6
= 48
4. Find NRT
NRT = N x R x T
= 2 x 6 x T
= 12 x T
= 12T
5. Find T
PV = NRT
48 = 12T
12T = 48
divide both sides by 12
T = 48 ÷ 12
T = 4
Answer:
3 cm base, 6 cm height
Step-by-step explanation:
base is already labeled and the height is as well
First we need to put it in slope intercept form (solve for y). Then we get tex]y= -\frac{2}{3} x+490[/tex]. So the slope is-2/3 and the y intercept is 490.
