Our discriminant is 0 so,
has one real root.
Option C is correct.
Step-by-step explanation:
we need to find the discriminant and the number of real roots for the following equation:

The discriminant is found by using square root part of quadratic formula:

where b =12, a=4 and c=9
Putting values:

To find out the number of real roots using discriminant we have following rules:
- if discriminant b^2-4ac >0 then 2 real roots
- if discriminant b^2-4ac =0 then 1 real root
- if discriminant b^2-4ac <0 then no real roots
Since our discriminant b^2-4ac is 0 so,
has one real root.
Option C is correct.
Keywords: discriminant
Learn more about discriminant at:
#learnwithBrainly
Answer:
Step-by-step explanation:
My drawing tool is Desmos. It can be used at no cost.
the graph will not work unless you combine -2x^ and -4x^2 to give - 6x^2.
If you try and graph it as given, you get a straight line going for quadrant 4 to quadrant 2.
But you will note that when you make the addition of the 2 middle terms, it gives you the graph that I have enclosed, which is the one you should expect. I'm wondering why you get a straight line when you try and graph what you were given.
Hello!
You read scientific notation by moving the decimal that amount of spaces next the the 10
1.263 * 10^3
You move the decimal over 3 places
1.263 * 10^3 = 1263
The answer is 1.263 * 10^3
Hope this helps!
The answer is: x = 7 - √53 or x = 7 + √53
The general quadratic equation is: ax² + bx + c =
0.
But, by completing the square we turn it into: a(x + d)² + e = 0, where:<span>
d = b/2a
e = c - b²/4a
Our quadratic equation is x² - 14x -4 = 0, which is
after rearrangement:
So, a = 1, b = -14, c = -4
Let's first calculate d and e:
d = b/2a = -14/2*1 = -14/2 = -7
e = c - b²/4a = -4 - (-14)</span>²/4*1 = -4 - 196/4 = -4 - 49 = -53<span>
By completing the square we have:
a(x + d)² + e = 0
1(x + (-7))</span>² + (-53) = 0
(x - 7)² - 53 = 0
(x - 7)² = 53
x - 7 = +/-√53
x = 7 +/- √53
Therefore, the solutions are:
x = 7 - √53
or
x = 7 + √53
When you rotate 90 degrees clockwise, (x,y) becomes (y,-x).
Therefore:
G = (3,1)
H = (0, 4)
I = (-2, -3)