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Ierofanga [76]
3 years ago
8

A bag contains Red, Green and Yellow balls. A ball is taken at random from the bag. The probability that it is Red is 0.35 and t

he probability that it is Green is 0.4 Find the probability that ball selected is: one is yellow other is not red plz answer urgent
Mathematics
1 answer:
EleoNora [17]3 years ago
5 0

Answer:

0.25

0.65

Step-by-step explanation:

Looking at the question, we can see that we were not given the probability of selecting a yellow ball.

Hence the probability of this is;

1-0.35-0.4 = 1-0.75 = 0.25

The probability that the selected ball is yellow is 0.25

The probability that it is not red means it is either yellow or green

What this means is that we add the probability of yellow to the probability of green

= 0.25 + 0.4 = 0.65

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Select ALL the correct answers.
hichkok12 [17]

Answer: Jack, To Decide

Step-by-step explanation:

I am almost certain this is right.

The idea that it is random from a stranger especially between two sides, it fits the idea for fairness. Same with the citizens asked to participate and the random generator.

6 0
2 years ago
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An 18ft ladder leans against a house, reaching a point 14ft above the ground. How far is the foot of the ladder from the bottom
Arisa [49]

Answer: a^2+b^2=c^2

Step-by-step explanation: (18^2=14^2+c^2)=324=196+c^2

324-196=128 and the square root of 128 is 8 radical 2 or in decimal form 11.31

5 0
3 years ago
Read 2 more answers
A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

3 0
1 year ago
a mower uses 5/16 gallon of gas to mow the back yard. the side yard is only 2/3 the size of the backyard. How much gas will be n
Trava [24]

Answer:

(5/24) gallons of gas to mow the side yard

Step-by-step explanation:

We can easily solve this proble by applying a rule of three

5/16 gallons of gas  ---------------------------------  for 1 backyard

x  gallons of gas ------------------------------------- 2/3 backyard

x = ((2/3)/1)*(5/16) gallons of gas

x = ((2/3))*(5/16) gallons of gas

x = ((10/48) gallons of gas

x = (5/24) gallons of gas

3 0
3 years ago
Find the values of the sine, cosine, and tangent for ZA.<br><br> (TOP OF TRIANGLE IS (A))
Sloan [31]

\bigstar\:{\underline{\sf{In\:right\:angled\:triangle\:ABC\::}}}\\\\

  • AC = 7 m
  • BC = 4 m

⠀⠀⠀

\bf{\dag}\:{\underline{\frak{By\:using\:Pythagoras\: Theorem,}}}\\\\

\star\:{\underline{\boxed{\frak{\purple{(Hypotenus)^2 = (Perpendicular)^2 + (Base)^2}}}}}\\\\\\ :\implies\sf (AB)^2 = (AC)^2 + (BC)^2\\\\\\ :\implies\sf (AB)^2 = (AB)^2 = (7)^2 = (4)^2\\\\\\ :\implies\sf (AB)^2 = 49 + 16\\\\\\ :\implies\sf (AB)^2 = 65\\\\\\ :\implies{\underline{\boxed{\pmb{\frak{AB = \sqrt{65}}}}}}\:\bigstar\\\\

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━

☆ Now Let's find value of sin A, cos A and tan A,

⠀⠀⠀

  • sin A = Perpendicular/Hypotenus = \sf \dfrac{4}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{4 \sqrt{65}}{65}}

⠀⠀⠀

  • cos A = Base/Hypotenus = \sf \dfrac{7}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{7 \sqrt{65}}{65}}

⠀⠀⠀

  • tan A = Perpendicular/Base = {\sf{\pink{\dfrac{4}{7}}}}

⠀⠀⠀

\therefore\:{\underline{\sf{Hence,\: {\pmb{Option\:A)}}\:{\sf{is\:correct}}.}}}

4 0
3 years ago
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