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Veronika [31]
3 years ago
14

26=5(x+10)+3x whatsy answer how do I get it??

Mathematics
2 answers:
olga_2 [115]3 years ago
5 0
26 = 5 (x + 10) + 3x 
26 = 5x + 50 + 15x
26 = 5x +15x + 50
26 = 20x + 50
26 - 50 = 20x - 50
-14 = 20x
-14 / 20 = x
-0.7 = x
igor_vitrenko [27]3 years ago
3 0
26=5(x+10)+3x
26=5x+50+3x
26=8x+50
26-50=8x+50-50
-24=8x
x=-3
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PLEASE HELP ASAP (MATH)<br> WRITE IN STANDARD FORM!
sveticcg [70]
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<em>3×10⁵</em>

  • Step-by-step explanation:

<em>Hi there !</em>

<em />\frac{9.6*10^{7}}{3.2*10^{2}}=\\ \\=3*10^{7-2}\\ \\=3*10^{5}<em />

<em>Good luck !</em>

6 0
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An ostrich can run 174 feet in 3 seconds.
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Answer:

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Step-by-step explanation:

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2 years ago
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Inessa [10]

Answer: y=fx+4f

Step-by-step explanation:

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5 0
3 years ago
John is going on a trip and the country he is traveling to uses the Celsius scale. He is curious about converting Celsius temper
Setler79 [48]

Answer:

f(x)=\dfrac{9}{5}x+32 converts Celsius to Fahrenheit.

g(x)=\dfrac{5(x-32)}{9} converts Fahrenheit to Celsius.

Step-by-step explanation:

Write given data in the table

\begin{array}{cc}x&f(x)\\^{\circ}\text{C}&^{\circ}\text{F}\\20&68\\30&86\end{array}

Let the expression for the function be

f(x)=ax+b

Note, that this equation is linear equation and it is well-known fact that the Celsius to Fahrenheit dependence is linear.

Substitute corresponding values into this expression:

68=20a+b\\ \\86=30a+b

Subtract these two equations:

86-68=30a-20a\\ \\10a=18\\ \\a=\dfrac{9}{5}

Substitute it into the first equation:

68=20\cdot \dfrac{9}{5}+b\Rightarrow b=68-36=32

So,

f(x)=\dfrac{9}{5}x+32

This is the function which converts Celsius to Fahrenheit.

And function

g(x)=\dfrac{5(x-32)}{9} converts Fahrenheit to Celsius.

4 0
2 years ago
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A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Der
taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
<span>   Σ (2i + 3)
</span>i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
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