2x2=4
It is just like adding 2 twice
2 + 2 = 4
2 x 2 = 4
Answer:
A
Step-by-step explanation:
We are given two rational functions m(x) and n(x) that have the same vertical asymptotes both with a single x-intercept at x = 5.
The correct choice will be A.
Recall the transformations of functions.
B represents m(x) being shifted up 5 units. If the function is shifted up, the vertical asymptotes will be the same, but the x-intercept will change.
C represents m(x) being shifted 5 units to the right. This changes both the x-intercept and the vertical asymptotes.
Likewise, D represents m(x) being shifted 5 units to the left. Again, this will change both the x-intercept and the vertical asymptotes.
Therefore, the only choice left is A. It represents a vertical stretch by a factor of 5. This preserves the x-intercepts and the vertical asymptotes. Consider the function:

If n(x)=5m(x), we can see that:

So, the x-interceps and vertical asymptotes are preserved.
Answer:
verdadero
Step-by-step explanation:
Answer:
Outside of probability, Pascal's Triangle is also used for: Algebra, where coefficient of polynomials can be used to find the numbers in Pascal's triangle. Pascal's Triangle is an arithmetical triangle you can use for some neat things in mathematics.
The entries in Pascal's triangle are actually the number of combinations of N take n where N is the row number starting with N = 0 for the top row and n is the nth number in the row counting from left to right where the n = 0 number is the first number.
The mathematical formula for the number of combinations without repetition is N!/(n!(N-n)!).
Step-by-step explanation:
To construct Pascal's triangle, start with a 1. Then, in the next row, write a 1 and 1. It's good to have spacing between the numbers. In the third row, we have 1 and 1 on the outside slopes. The 2 comes from adding the two numbers above and adjacent. Thus, we are adding the number on the left, 1, with the number on the right, 1, to get 1 + 1 = 2.
In the next row, the 3 comes from adding the 1 and the 2. This particular Pascal's triangle stopped at 1 5 10 10 5 1, but we could have continued indefinitely.