A supply company manufactures copy machines. The unit cost C (the cost in dollars to make each copy machine) depends on the numb
er of machines made. If
x machines are made, then the unit cost is given by the function C(x) -0.4x-112x+17,167. What is the minimum unit cost? I got the answer $140 but apparently it was wrong.
x machines are made, then the unit cost is given by the function C(x) -0.4x-112x+17,167. What is the minimum unit cost? I got the answer $140 but apparently it was wrong.
1 answer:
Answer:
$9327
Step-by-step explanation:
Apparently, the cost function is supposed to be ...
C(x) = 0.4x^2 -112x +17167
This can be rewritten to vertex form as ...
C(x) = 0.4(x^2 -280) +17167
C(x) = 0.4(x -140)^2 +17167 -0.4(19600)
C(x) = 0.4(x -140)^2 +9327
The vertex of the cost function is ...
(x, C(x)) = (140, 9327)
The minimum unit cost is $9327.
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<em>Comment on the question</em>
You found the number of units that result in minimum cost (140 units), but you have to evaluate C(140) to find the minimum unit cost.
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The equation is 
the -30 expression, is subtracting, if negative, from the 60
if the cosine returned is negative, you'd end up with a +30,
negative * negative = positive
and then the 30 expression will ADD to the 60 amount
so the temperature "t" is highest, when the 30 expression, is
positive and and it's highest
when does that happen, when cosine is negative and at its highest,
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so... let's find a value that makes that expression to
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so...for August, that'll mean
the -30 expression, is subtracting, if negative, from the 60
if the cosine returned is negative, you'd end up with a +30,
negative * negative = positive
and then the 30 expression will ADD to the 60 amount
so the temperature "t" is highest, when the 30 expression, is
positive and and it's highest
when does that happen, when cosine is negative and at its highest,
well, cosine range is
so the lowest value cosine can provide is -1, when is cosine -1?
well, at
so... let's find a value that makes that expression to
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so...for August, that'll mean
To calculate the relative vector of B we have to:
The coordenates of:
, with respect to B satisfy:
Equating coefficients of like powers of t produces the system of equation:
After solving this system, we have to:
And the result is:
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