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Arte-miy333 [17]
3 years ago
9

A supply company manufactures copy machines. The unit cost C (the cost in dollars to make each copy machine) depends on the numb

er of machines made. If
x machines are made, then the unit cost is given by the function C(x) -0.4x-112x+17,167. What is the minimum unit cost? I got the answer $140 but apparently it was wrong.

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
8 0

Answer:

  $9327

Step-by-step explanation:

Apparently, the cost function is supposed to be ...

  C(x) = 0.4x^2 -112x +17167

This can be rewritten to vertex form as ...

  C(x) = 0.4(x^2 -280) +17167

  C(x) = 0.4(x -140)^2 +17167 -0.4(19600)

  C(x) = 0.4(x -140)^2 +9327

The vertex of the cost function is ...

  (x, C(x)) = (140, 9327)

The minimum unit cost is $9327.

_____

<em>Comment on the question</em>

You found the number of units that result in minimum cost (140 units), but you have to evaluate C(140) to find the minimum unit cost.

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Step-by-step explanation:

5+15+20=40

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In Illinois, 9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been arre
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Answer:

a) 21.58% probability that exactly 3 people are repeat offenders

b) 97.91% probability that at least one person is a repeat offender

c) 3.69

d) 1.83

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders

This means that p = 0.09

41 people arrested for DUI in Illinois are selected at random.

This means that n = 41

a. What is the probability that exactly 3 people are repeat offenders?

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{41,3}.(0.09)^{3}.(0.91)^{38} = 0.2158

21.58% probability that exactly 3 people are repeat offenders

b. What is the probability that at least one person is a repeat offender?

Either none are repeat offenders, or at least one is. The sum of the probabilities of these outcomes is 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1).

Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = 0) = C_{41,0}.(0.09)^{0}.(0.91)^{41} = 0.0209

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0209 = 0.9791

97.91% probability that at least one person is a repeat offender

c. What is the mean number of repeat offenders?

E(X) = np = 41*0.09 = 3.69

d. What is the standard deviation of the number of repeat offenders?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{41*0.09*0.91} = 1.83

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