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3 years ago

9

When a metallic ball bearing is placed inside a cylindrical container, of radius 2 cm, the height of the water, inside the conta

iner, increases by 0.6 cm. The radius, to the nearest tenth of a centimeter, of the ball bearing is

1 answer:

Elan Coil [88]3 years ago

7 0

It will be 1.2 cm,......

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2 years ago

BRAINLIEST FOR BEST ANSWER!!!

sertanlavr [38]

less than; Set A

It is less than, because if you add half of the sum of the least and greatest numbers of the set to the lowest number in the set, you get the median. The median of Set A was 17, and the Median of Set B was 17.5.

Set A is more variable in terms of range, because it has a larger range.

4 0

2 years ago

Differentiate y=x⁴(1-2x⁵)⁶(5-8x³)².

Liula [17]

Step-by-step explanation:

Let $y(x)=f(x)g(x)h(x)$ where

$f(x) = x^4$

$g(x)= (1 -2x^5)^6$

$h(x)= (5 - 8x^3)^2$

so that

$y(x) = x^4(1 -2x^5)^6(5 - 8x^3)^2$

Recall that the derivative of the product of functions is

$y'(x)=f'(x)g(x)h(x)+f(x)g'(x)h(x)+f(x)g(x)h'(x)$

so taking the derivatives of the individual functions, we get

$f'(x) = 4x^3$

$g'(x) = 6(1 - 2x^5)^5(-10x^4)$

$h'(x) = 2(5 - 8x^3)(-24x^2)$

So the derivative of y(x) is given by

$y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2 + x^4 6(1 -2x^5)^5(-10x^4)(5 - 8x^3)^2 + x^4(1 -2x^5)^6 2(5 - 8x^3)(-24x^2)$

or

$y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 60x^8(1 -2x^5)^5(5 - 8x^3)^2$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 48x^6(1 -2x^5)^6 2(5 - 8x^3)$

3 0

2 years ago

Simplifying an algebra -3(y+2)

Brrunno [24]

Answer: -9y

Step-by-step explanation:

Step1: -3 is multiplied by y = -3y

Step 2: -3 multiplied by 2 = -6

Step 3: -3y + -6

6 0

3 years ago

Can someone please help me with this question?

sattari [20]

The answer would be y=1/7x-4

7 0

2 years ago