The experimental probability is
(number of times it stopped over Sect. 2) / (total number of times you tried it)
Number of times it stopped in Section-2: 36
Total number of times you tried it: (20 + 36 + 24) = 80
Experimental probability of Section-2 = 36/80 = 9/20 = 45%
Answer: 0.8413
Step-by-step explanation:
Given : The scores on a test have a normal distribution with mean 24 and standard deviation 4.
i.e. 
and 
Let x denotes the scores on the test.
Then, the probability that a student score less than 28 will be :-
Hence, the the proportion of scores less than 28 is 0.8413 .
The difference between the 6th term and the 9th term of the sequence is 135
<h3>How to determine the difference</h3>
Given that the nth term is;
3n² + 11
For the 6th term, the value of n is 6
Let's solve for the 6th term
= 3( 6)^2 + 11
= 3 × 36 + 11
= 108 + 11
= 119
For the 9th term, n = 9
= 3 (9)^2 + 11
= 3( 81) + 11
= 243 + 11
= 254
The difference between the 6th and 9th term
= 254 - 119
= 135
Thus, the difference between the 6th term and the 9th term of the sequence is 135
Learn more about algebraic expressions here:
brainly.com/question/4344214
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Wouldn’t it be 36.7 because that’s the arch am I right?
Answer:
it will cost 240$ dollars to pay for 5 month
Step-by-step explanation:
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