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3 years ago

Please help, I'm running out of points.

Mathematics

1 answer:

aksik [14]3 years ago

3 0

Answer:

−5 < x < 10

Step-by-step explanation:

Add 1 to each part of the three parts of the inequality:

-6 +1 < x - 1 +1 < 9 +1

-5 < x < 10 . . . . . simplify

_____

The only place where there's an x is in the middle section. The only operation performed on x is subtraction of 1. To undo that subtraction, you add 1, but you must add 1 to all sides of the comparison symbols in order to keep them true.

Such a compound inequality is the same as the two inequalities:

-6 < x-1
x-1 < 9

Solving either one of these is done by adding 1 to both sides of the < symbol:

-5 < x
x < 10

You can put these back together in the form of the compound inequality ...

-5 < x < 10

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Simplify 4√16 + 8√16

Mumz [18]

$4\sqrt{16} + 8\sqrt{16}$ :

Since $\sqrt{1} =1$ , we get:

$4\cdot \:1\cdot \:6+8\cdot \:1\cdot \:6=24+48=72$

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$7\sqrt{4} *3\sqrt{8}$

We have $\sqrt{4}=2$

simplify $\sqrt{8} = \sqrt{2^3} = \sqrt{2^2*2}$

then the radical rule is used: $\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}$

⇒ $\sqrt{2^2*2} = \sqrt{2^2} \sqrt{2}= \sqrt{4}\sqrt{2} =2\sqrt{2}$

Now we have $\sqrt{4}=2$ and $\sqrt{8}=2 \sqrt{2}$

$7\sqrt{4} *3\sqrt{8} = 7*2*3*2\sqrt{2} = 84 \sqrt{2}$

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$2\sqrt{4}+5 \sqrt{9}$

$2\sqrt{4} =2*2= 4$ and $5\sqrt{9} =5*3= 15$

$2\sqrt{4}+5 \sqrt{9} = 4+15 = 19$

-----------------------------------------------------------------------------------

$4\sqrt{5} -2\sqrt{5} = 2\sqrt{5}$

since $2\sqrt{5}$ is the half of $4\sqrt{5}$

-----------------------------------------------------------------------------------

$-4\sqrt{2}\:+\:5\sqrt{2} =1 \sqrt{2} = \sqrt{2}\\$ (-4+5=1)

4 0

3 years ago

8(x + 2) = 48 How do I solve this?

Rufina [12.5K]

You distribute the 8 to the x and the 2 which leaves you with 8x + 16 = 48 then u subtract the 16 on both sides, subtract 16 - 16 (cancel out) then 48-16 which gives you 32, from there you should have 8x=32 then you divide 8x by 8 and 32 by 8 which leave the x by itself and you 32/8 is 4 so the final answer is x = 4 !!

7 0

4 years ago

Read 2 more answers

URGENT!! Given the inequality, the test point (2,-8) .... a) b) c) d)

sattari [20]

Answer:

Step-by-step explanation:

let's see, I'd the point on the line/boundary ?

for this we use the equality part (and use the coordinates of the point as x and y) :

-8 = 2×2² - 5×2 - 6 = 8 - 10 - 6 = -2 - 6 = -8

correct.

this proves that the point is on the line defined by the equation.

and that means it is on the boundary of the inequality.

because that inequality contains the boundary in the solution region (hence the >= relation instead of just >), we cannot use that point to determine which side of the boundary (incl. the boundary line, but still) is the solution region.

3 0

3 years ago

In each figure below find m∠1 and m∠2, if a||b. Show your work with statements.

quester [9]

ANSWER

$m < \: 1 = 80 \degree$

$m < \: 2= 70 \degree$

EXPLANATION

Since

$a || b$
line s and t are both transversals.

This implies that,

$m < \: 1 \: and \: 80 \degree$

are alternate angles.

Alternate angles are equal. Therefore,

$m < \: 1 = 80 \degree$

Also,

$m < \: 2= 70 \degree$

because corresponding angles are equal.

6 0

3 years ago

Find the vertex of this quadratic.

Paraphin [41]

Answer:

(-3, 0)

Step-by-step explanation:

As per the graph the vertex, the maximum of the quadratic function is (-3, 0)

6 0

3 years ago