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3 years ago

Find the volume of the prism

Mathematics

1 answer:

Crank3 years ago

8 0

Answer: i dont know how to solve 3D triangle shapes

Step-by-step explanation:

this is not a prisim

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Identify the shape of the distribution, and (b) determine the five-number summary. Assume that each number in the five-numbe

Marat540 [252]

1. The shape of the distribution is: B. skewed left.

2. he five-number summary is: 0, 14, 17, 18, 20.

<h3>What is Left-skewed Distribution?</h3>

If the data distribution that is represented by a box plot is left-skew (negatively skewed), the median will appear closer to the third quartile (Q3) of the box plot. The median is at the point where a vertical line divides the box into two.

Part 1: The box plot shows that the median is close to the third quartile, therefore, the shape of the distribution is described as: B. skewed left.

Part 2: The five-number summary include:

Min. value = 0

Q1 = 14

Median = 17

Q3 = 18

Max. value = 20.

Learn more about left-skewed distribution on:

brainly.com/question/15759915

#SPJ1

4 0

2 years ago

Please help math questions put number with answers please

natita [175]

Answer:

See below for answers

Step-by-step explanation:

Problem 1

$\frac{1}{sin\theta}=2cos\theta\: ; \: 0\leq\theta < 2\pi\\\\1=2sin\theta cos\theta\\\\1=sin2\theta\\\\\frac{\pi}{2}+2\pi n=2\theta\\ \\\frac{\pi}{4}+\pi n=\theta\\ \\\theta=\bigr\{\frac{\pi}{4},\frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\bigr\}$

Therefore, the second option is correct.

Problem 2

$cos(2x)+1=sin(x)+2\:;\: 0\leq x < 2\pi\\\\1-2sin^2x+1=sin(x)+2\\\\-2sin^2x=sin(x)\\\\0=2sin^2x+sinx\\\\0=sinx(2sinx+1)$

$0=sinx\\\\x=\pi n\\\\x=0,\pi$

$0=2sinx+1\\\\-1=2sinx\\\\-\frac{1}{2}=sinx\\ \\x=\frac{7\pi}{6}+2\pi n,\frac{11\pi}{6}+2\pi n\\\\x=\frac{7\pi}{6},\frac{11\pi}{6}$

Therefore, the solution set is $x=\bigr\{0,\pi,\frac{7\pi}{6},\frac{11\pi}{6}\bigr\}$ , making the second option correct.

Problem 3

$2cos^2x=-cosx\: ;\: 0^\circ\leq x < 360^\circ\\\\2cos^2x+cosx=0\\\\cosx(2cosx+1)=0$

$cosx=0\\\\x=\frac{\pi}{2}+\pi n\\ \\x=90^\circ+180n^\circ\\\\x=90^\circ,270^\circ$

$2cosx+1=0\\\\2cosx=-1\\\\cosx=-\frac{1}{2}\\\\x=\frac{2\pi}{3}+2\pi n,\frac{4\pi}{3}+2\pi n\\ \\x=120^\circ+360n^\circ,240^\circ+360n^\circ\\\\x=120^\circ,240^\circ$

Therefore, the solution set is $x=\bigr\{90^\circ,120^\circ,240^\circ,270^\circ\bigr\}$ , making the fourth option correct

7 0

2 years ago

Plz help no guessing

ankoles [38]

Your answer would be C. 6.07 × 10^24.

This is because to add numbers in standard form, we need to get their (×10^x) to be the same, as in, we need to get 7 × 10^22 to be [value] × 10^24.

To convert ×10^22 to ×10^24, we need to divide 7 by 100, as 0.07 × 10^24 = 7 × 10^22.

Now that we have them both with the same power, we can add 6 to 0.7 to get 6.07 × 10^24.

I hope this helps! Let me know if you have any questions because my explanation was a bit strange :)

6 0

3 years ago

Solve for x: 2x - 3+ 4x = 27 answers x=4 x=5 x=12 x=15

MrRa [10]

Answer:

x=5

Step-by-step explanation:

2x-3+4x=27

6x-3=27

6x=27+3=30

x=30/6

x=5

6 0

3 years ago

The rabbit population on a small island is observed to be given by the function P(t) = 130t − 0.4t^4 + 1200 where t is the time

olya-2409 [2.1K]

A.) P(t) = 130t - 0.4t^4 + 1200
The population is maximum when P'(t) = 0
P'(t) = 130 - 1.6t^3 = 0
1.6t^3 = 130
t^3 = 81.25
t = ∛81.25 = 4.3 months.

Maximum population P(t)max = 130(4.3) - 0.4(4.3)^4 + 1200 = 1,622

b.) The rabbit population will disappear when P(t) = 0
P(t) = 130t - 0.4t^4 + 1200 = 0
t ≈ 8.7 months

3 0

3 years ago

Read 2 more answers