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Andrej [43]
3 years ago
6

Can someone please help me with this one math question?

Mathematics
1 answer:
Valentin [98]3 years ago
5 0

You have:

y = x^2 +5x-3

and

y-x = 2


replace y in the 2nd equation with what Y equals in the first equation:


x^2 +5x-3 - x = 2

Subtract 2 from both sides of  the equation:

x^2 +5x-3 - x -2 = 0

Simplify:

x^2 +4x -5 = 0

Factor:

(x-1) (x+5) = 0


Solve for the x's:

1-1 = 0

-5 +5 = 0

X = 1, -5



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40%

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5 Multiply both sides by
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4 0
3 years ago
Hoang has worked as a nurse at Springfield General Hospital for 5 years longer than her friend Bill Two years ago she has been a
satela [25.4K]

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Hoang has been at the hospital for 12 years while Bill has worked for 7 years.

Step-by-step explanation:

Let the years Hoang has worked as a nurse equal h and let the years Bill has worked as a nurse equal b.

Since Hoang has worked 5 years longer, h is five more than b:

h = b + 5

Now we move onto the situation 2 years ago. 2 years ago, Hoang had worked at the hospital two less than h or h-2 years while Bill has worked for b-2 which is two years less than b. We are also told that at the time, Hoang worked twice as longs, so

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Therefore, since Hoang has worked five more years, h = 12. So, Hoang has been at the hospital for 12 years while Bill has worked for 7 years.

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4 years ago
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