That's a true fact. If you want to get really technical, the area of a circle is. ALWAYS irrational because it's the product of something and PI.
The area that the dog can wander based on the information provided will be 931π.
<h3>How to calculate the area?</h3>
From the information, we are told that the dog dog is attached to a 35-foot rope fastened to the outside corner of a fenced-in garden that measures 28 feet by 36 feet.
In this case, the dog is in an outside corner. The dog can trace 3/4 of a circle when it starts walking in a circle away form the wall.
The area that the dog can wander will be:
= 3/4(π35²) + 1/4(π(35 - 28)²)
= 3/4π(35)² + 1/4π(7)²
= (3/4 × 1225)π + (1/4 × 49)π
= 918.75π + 12.25π
= 931π
Therefore, the area that the dog can wander based on the information provided will be 931π.
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The value of the output r(-3) in the given function is 2.
<h3>How to Interpret Graphs?</h3>
When we talk about graphs like this, it is pertinent to note that the x-values are the input values which would give us corresponding y-values which are the output values.
Now, we want to find r(-3) from the graph. This means we want to find the value on the y-axis when x = -3.
From the given graph, we see that when x = - 3, it is traced that the value of the output is y = 2.
Thus, the value of the output r(-3) in the given function is 2.
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Slope=y2-y1/x2-x1
slope=((5/2)-4)/4-2
slope=((4/2)-4)/2
don't got a calc on me :S but hope you can complete it
9514 1404 393
Answer:
p = 3x+10
Step-by-step explanation:
The attached diagram pretty much explains it.
The unknown dimension at the top was the subject of a previous problem. It is the difference in length between the two marked horizontal segments:
(2x +15) -(x) = x +15 . . . . . length of unmarked solid horizontal line
Similarly, the length of the unmarked vertical line on the right is the difference between the marked vertical lines:
(2x -5) -(x -5) = x . . . . . length of unmarked solid vertical line
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The formula for the area of a rectangle is used to find the areas of the left-side and right-side rectangles. Respectively, those areas are ...
left-side area = x(2x -5)
right-side area = x(x +15)
Then the total area enclosed by the solid line is ...
x(2x -5) +x(x +15) = x(2x -5 +x +15) = x(3x +10)
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The area of the lot extension is the product of its dimensions:
extension area = x·p
We want this to be the same as the area in the solid line, so ...
x·p = x·(3x +10)
Dividing by the coefficient of p (which is x), we have ...
p = 3x +10
