All categories

3 years ago

The cost of John’s bike(p) cannot exceed $5,000. Write this sentence in the form of a set notation.

Mathematics

1 answer:

lakkis [162]3 years ago

5 0

Answer:

$p = \{x \ | \ x \in Q^+ \ and \ x \leq \$5,000 \}$

Step-by-step explanation:

The expression for the cost of John's bike (p) using set notation can written as follows;

We note that the cost of the bike is a member of the positive rational number and the cost price of the bike cannot exceed $5,000, therefore, it is less than or equal to $5,000, therefore, we get the following set notation;

$p = \{x \ | \ x \in Q^+ \ and \ x \leq \$5,000 \}$

You might be interested in

Slide 4

goldenfox [79]

Answer:

87.5$ since 25% is 1/4 87.5 is 1/4

Step-by-step explanation:

4 0

3 years ago

The perimeter of a square varies directly with the length of one side. what is an equation that relates the perimeter p and leng

PilotLPTM [1.2K]

P=KL where K is the constant of variation

4 0

4 years ago

Help me and thx alot

Svet_ta [14]

Answer:

easyyyyyyy

Step-by-step explanation:

table J!

8 0

3 years ago

The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe

juin [17]

The height of container is 8 feet

Solution:

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

The volume of container is given as:

$v = length \times width \times height$

Given that volume of the container is 216 cubic feet

$216 = l \times w \times h$

Substitute eqn 1 and eqn 2 in above formula

$216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0$

Solve by factoring

$(h-8)(h^2+4h+27) = 0$

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

$h - 8 = 0\\\\h = 8$

Also,

$h^2+4h+27 = 0$

Solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}$

$h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}$

Therefore, on solving we get,

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

Thus solutions of "h" are:

h = 8

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0

3 years ago

See image help me as fast as possible, please

Arada [10]

Answer: 11.4

Step-by-step explanation:

area of rect. = 24

area of circle (half circle+half circle = full circle) = pi*r^2 = pi*(2*2) = pi*4 = about 12.57

2 = radius since 4 = diameter

24-12.57 = 11.43

round = 11.4

3 0

3 years ago

Read 2 more answers