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slavikrds [6]
3 years ago
13

What is a expression that equals 3/8? Like a written out expression?​

Mathematics
1 answer:
Leno4ka [110]3 years ago
3 0

Answer: not sure what this question means but i assume three eighths or 0.375

Depends on context

Step-by-step explanation:

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Find the slope of the vertical line that passes through (2,-4)
makkiz [27]

Answer:

x=2

Step-by-step explanation:

Vertical lines have the same x value all the time.  It is of the form x=

Their slope is undefined

The line passes through the point (2,4) and the x value is 2

x=2

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Consider The Graph shown?
dmitriy555 [2]

Answer:

y = 1/2x + 2

Comparison: The black and blue line haver the same y-intercept, however they have different slopes. The slope of the black line is 2/3 and the slope of the blue line is 1/2.

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3 years ago
50 POINTS AND BRAINLIEST 3. Write an inequality of the form Ax + B ≤ C to represent the word problem using your answers for A, B
lisabon 2012 [21]

Answer:

Step-by-step explanation:

A possible word problem for 3x+10 ≤75 could be

Mat has $75 dollars saved in his wallet and wants to use it for go carts. Knowing that the entrance to the park is $10, and each time around the go cart course is $3 what is the maximum times he can go around?

3x+10 ≤ 75, subtract 10 from both sides

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 or  x ≤ 21.(6)

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4 0
3 years ago
In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.
Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}


In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, B. Then, we can find the third side. Using the law of sines, we can find:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}


We can use this to solve for B:

13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}

B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1


Now, we can find C:

C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}


Using this, we can find c:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}

c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}


c is approximately 17.5.

8 0
3 years ago
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