All categories

3 years ago

A ÷ 9 = 81 What must I do to both sides to solve for ¨a¨

Mathematics

1 answer:

stiks02 [169]3 years ago

8 0

Answer:

a=729

Step-by-step explanation:

Solve for a by simplifying both sides of the equation, then isolating the variable.

You might be interested in

Starting value 100 increases 5%

Brut [27]

Answer:

105

Explanation:

Adding 5% of 100, to 100 is:

100(0.05) + 100

The extra 100 is added because 100(0.05) only gives you what 5% of 100 is.

3 0

3 years ago

How does using a model help me multiply decimals by whole numbers?

valkas [14]

Counting them it simple

5 0

3 years ago

6) Evaluate for x = 3:<br> 3•4x/2

Nikolay [14]

Answer:

Step-by-step explanation:

3×4(x)/2

Plug in 3 to x

3×4(3)/2

3×12/2

36/2

5 0

3 years ago

Help!

svet-max [94.6K]

Question 1. 7:11
Question 2. 27 units of K

How to solve the questions-
1. 14/22 divide the numerator and the denominator by 2. This would give you 7/11

2. If the ratio is 12/9 and the amount of N is 36, you’re basically multiplying 12 *3, so then you have to multiply 9 *3=27.

6 0

3 years ago

Find the area of the shaded region.f(x)=4x+3x2−x3,g(x)=0<br> The area is _____.

Tasya [4]

Answer:

The answer is " $\bold{\frac{7}{2}}$ "

Step-by-step explanation:

Given value:

$\to f(x)=4x+3x^2-x^3\\\\\to g(x)=0$

Find:

area=?

calculation:

$\ Area = \int_{-1}^{0} -(4x+3x^2-x^3) dx + \int_{0}^{1} (4x+3x^2-x^3) dx \\\\$

$= -(2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= -( 2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= ( 2- 1 -\frac{1}{4}) + (2+1- \frac{1}{4})\\\\\\= ( \frac{8-4-1}{4}) + (\frac{8+4-1}{4})\\\\= ( \frac{3}{4}) + (\frac{11}{4})\\\\= \frac{3}{4} + \frac{11}{4}\\\\= \frac{11+3}{4}\\\\= \frac{14}{4}\\\\= \frac{7}{2}\\\\$

7 0

3 years ago