Just use the order of operations. PEMDAS, parentheses, exponents, multiplication, division, addition and subtraction.
In the first problem 2 + 6*3^2, there are no parentheses, so next would be exponents.
There is an exponent so you do that first.
3^2 = 9
Now we have 2 + 6*9
Multiplication is next and it is in the problem, so we do 6*9 = 54
So now we have 2 + 54 which equals 56.
The answer is 24. you round up.
Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
|4| > |1|
Absolute value of 4 is just 4, and the abosulute valvue of 1 is just 1.
So , since 4 is greater than 1 , that would be your answer.
4 > 1