Answer:
a. p(orange) = 5/14
b. p(green) = 3/14
c. p(red) = 1/7
d. p(brown) = 2/7
e. p(brown or red) = 3/7
Step-by-step explanation:
1. You have a 14 pencils. Two pencils are red, 5 pencils are orange, 3 pencils are green and 4 pencils are brown.
p(color) = (number of pencils of that color)/(total number of pencils)
p(color) = (number of pencils of that color)/14
a. If a pencil is picked at random, what is the probability that the pencil
will be orange?
p(orange) = 5/14
b. If a pencil is picked at random, what is the probability that the pencil
will be green?
p(green) = 3/14
c. If a pencil is picked at random, what is the probability that the pencil will be red?
p(red) = 2/14 = 1/7
d. If a pencil is picked at random, what is the probability that the pencil
will be brown?
p(brown) = 4/14 = 2/7
e. If a pencil is picked at random, what is the probability that the pencil
will be brown or red?
brown: 4
red: 2
brown or red: 4 + 2
p(brown or red) = 6/14 = 3/7
Answer:
I think the answer is 3 option
Answer: B
Step-by-step explanation:
If a polynomial with real coefficient has a complex zero, the conjugate of that number will be a zero as well.
So, if 4-6i is a zero, 4+6i will be a zero as well
If -2+11i is a zero, -2-11i will be a zero as well
So, the zeroes are
if the given point satisfies this equation then it would be its solution
(-1)=2(5)-11
-1=10-1
-1=-1
lHS=RHS
Hence (/,-1) is the solution of y=2x-11
