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bonufazy [111]
3 years ago
7

What is the slope and the y-intercept of the line on the graph below? On a coordinate plane, a line goes through points (0, 1) a

nd (4, 0).
Mathematics
2 answers:
krok68 [10]3 years ago
5 0

Answer:

slope = Negative one-fourth, y-intercept = 1

Step-by-step explanation:

DedPeter [7]3 years ago
3 0

The slope is the change in Y over the change in x:

Slope = (0-1) / 4-0) = -1/4

Slope = -1/4

Y intercept is the Y value when x is equal to 0. In the point (0,1) x is 0 and y is 1, so the y-intercept is 1

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A variable for 7 to the 3rd power
topjm [15]

7x7x7, I think so not entirely sure. But 7³ is 7x7x7 it's not 7x3

3 0
3 years ago
Read 2 more answers
Which fraction is greater 36/126 or 42/126?
trapecia [35]
Since both fractions have the same denominator, to find the greater one all you have to do is see which one has a bigger numerator
42>36
the answer is 42/126 is greater
6 0
3 years ago
Marci has a total 50 stamps, consisting of 25 cent stamps and halves the number of 15 cent stamps, they will be worth of $16.50.
lukranit [14]

Answer:

Originally there were 30, 25 cents stamps and 20, 15 cent stamps.

Step-by-step explanation:

We are given the following in the question;

Let x be the number of 25 cents stamps and y be the number of 15 cents stamps.

Marci has a total 50 stamps.

Thus, we can write

x+y=50

Also,

x = \dfrac{y}{2}

Total cost = $16.50

Thus, we can write the equation:

0.25x + 0.15y = 16.50

Solving the two equations:

0.25\dfrac{y}{2} + 0.15y = 16.50\\\\(0.125+0.15)y = 16.50\\y = 60\\x = 30

Originally,

x+y = 50\\30 + y = 50\\y = 20

Thus, originally there were 30, 25 cents stamps and 20, 15 cent stamps.

7 0
3 years ago
Suppose that the data for analysis includes the attributeage. Theagevalues for the datatuples are (in increasing order) 13, 15,
Bas_tet [7]

Answer:

a) \bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96

Median = 25

b) Mode = 25, 35

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

c) Midrange = \frac{70+13}{3}=41.5

d) Q_1 = \frac{20+21}{2} =20.5

Q_3 =\frac{35+35}{2}=35

e) Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

f) Figura attached.

g) When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

Step-by-step explanation:

For this case w ehave the following dataset given:

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70.

Part a

The mean is calculated with the following formula:

\bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96

The median on this case since we have 27 observations and that represent an even number would be the 14 position in the dataset ordered and we got:

Median = 25

Part b

The mode is the most repeated value on the dataset on this case would be:

Mode = 25, 35

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

Part c

The midrange is defined as:

Midrange = \frac{Max+Min}{2}

And if we replace we got:

Midrange = \frac{70+13}{3}=41.5

Part d

For the first quartile we need to work with the first 14 observations

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25

And the Q1 would be the average between the position 7 and 8 from these values, and we got:

Q_1 = \frac{20+21}{2} =20.5

And for the third quartile Q3 we need to use the last 14 observations:

25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70

And the Q3 would be the average between the position 7 and 8 from these values, and we got:

Q_3 =\frac{35+35}{2}=35

Part e

The five number summary for this case are:

Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

Part f

For this case we can use the following R code:

> x<-c(13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70)

> boxplot(x,main="boxplot for the Data")

And the result is on the figure attached. We see that the dsitribution seems to be assymetric. Right skewed with the Median<Mean

Part g

When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

6 0
3 years ago
What is the quotient for the equation above?
Vladimir [108]

Answer:

The correct answer is 32.5

8 0
3 years ago
Read 2 more answers
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