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Furkat [3]
3 years ago
10

Find the LCD in this problem please!!!

Mathematics
1 answer:
Rom4ik [11]3 years ago
5 0

Answer:

the answer is 36xy squared

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Use the rectangle below to answer both parts of the question.
trasher [3.6K]

Answer:

part 1= "72=(2w)+(w-15)"

part 2= "29"

I'm not sure if they want "w = abc"

I used that equation to solve part 2

Hope this helps you, I've been where you are

6 0
2 years ago
Integrate this two questions ​
tankabanditka [31]

Simplify the integrands by polynomial division.

\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)

\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)

Now computing the integrals is trivial.

5.

\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}

where we use the power rule,

\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)

and a substitution to integrate the last term,

\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)

8.

\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}

using the same approach as above.

5 0
2 years ago
I'll mark you the brainliest
Arada [10]

Answer:

C.2

Step-by-step explanation:

Kase pinag papalus lang yan

I hope makatulong

and Pa follow narin po plss

5 0
2 years ago
Read 2 more answers
I’ll give brainlest if you answer this question correctly!
ycow [4]

Answer:

initial rate of change was 230 ft/s

the rate is not constant and the rate of change slows down

7 0
2 years ago
Solve for value of y FOR BRAINLIEST PLEASE :)
labwork [276]
90-51=39
9*5-6= 39
Y is 5
6 0
3 years ago
Read 2 more answers
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