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LuckyWell [14K]
3 years ago
8

50 POINTS!! Please help tysm :) image is attached (sorry about the quality); find the value of x. the answer key says x=10, but

I'm not sure how to get there.
please don't put an unrelated answer or just repeat the answer for the points :) I would like a step by step explanation ​

Mathematics
1 answer:
natima [27]3 years ago
6 0

Answer:

\: x = 10

Step-by-step explanation:

prefer the attachment

according to the question

\displaystyle \:  \frac{6}{17.5-x}  =  \frac{8 + 6}{17.5}

simplify addition:

\displaystyle \:  \frac{6}{17.5-x}  =  \frac{14}{17.5 }

simplify fraction;

\displaystyle \:  \frac{6}{17.5 - x}  = 0.8

cross multiplication:

\displaystyle 6 = 14 - 0.8x

cancel 14 from both sides:

\displaystyle - 8=  - 0.8x

divide both sides by -0.8:

\therefore \: x = 10

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Lizzy had test scores of: 72, 94, 108, 60What is the RANGE of her test scores?
Misha Larkins [42]

Answer:

48

Step-by-step explanation:

To find the range, you have to subtract the biggest/largest number by the smallest number:

108 - 60 = 48

The range is 48.

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The histogram shows the number of items sold at The Clothes Horse one week. About what percent of items sold cost less than $40
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I’m pretty sure the correct answer to this is D
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A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of t
Tomtit [17]

Answer:

0.54\,\,m^3

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

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To find: total volume of one big locker and one small locker

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Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= 0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6

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4 0
3 years ago
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Determine the astm grain size number if 33 grains per square inch are measured at a magnification of 270×
strojnjashka [21]
8.9

The equation for the grain size is expressed as the equality:
Nm(M/100)^2 = 2^(n-1)
where
Nm = number of grains per square inch at magnification M.
M = Magnification
n = ASTM grain size number

Let's solve for n, then substitute the known values and calculate.
Nm(M/100)^2 = 2^(n-1)

log(Nm(M/100)^2) = log(2^(n-1))
log(Nm) + 2*log(M/100) = (n-1) * log(2)
(log(Nm) + 2*log(M/100))/log(2) = n-1
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(log(33) + 2*log(270/100))/log(2) + 1 = n
(1.51851394 + 2*0.431363764)/0.301029996 + 1 = n
(1.51851394 + 0.862727528)/0.301029996 + 1 = n
2.381241468/0.301029996 + 1 = n
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So the ASTM grain size number is 8.9

If you want to calculate the number of grains per square inch, you'd use the
same formula with M equal to 1. So:
Nm(M/100)^2 = 2^(n-1)
Nm(1/100)^2 = 2^(8.9-1)
Nm(1/10000) = 2^7.9
Nm(1/10000) = 238.8564458
Nm = 2388564.458

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Answer:

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Step-by-Step Explanation:

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