m∠FDE = 52°
Solution:
Given data:
DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠ABF + m∠CBF = 180°
116° + m∠CBF = 180°
m∠CBF = 64°
If CD || BE, then CD || BF.
Hence CD || BE and BE || FD.
Therefore BFCD is a parallelogam.
<em>In parallelogram, Adjacent angles form a linear pair.</em>
m∠CBF + m∠BFD = 180°
64° + m∠BFD = 180°
m∠BFD = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠BFD + m∠DFE = 180°
116° + m∠DFE = 180°
m∠DFE = 64°
we know that DE ≅ DF.
<em>In triangle, angles opposite to equal sides are equal.</em>
m∠DFE = m∠DEF
m∠DEF = 64°
<em>sum of all the angles of a triangle = 180°</em>
m∠DFE + m∠DEF + m∠FDE = 180°
64° + 64° + m∠FDE = 180°
m∠FDE = 52°
Answer:
f(10) = 3(10) - 2 = 28
Step-by-step explanation:
Answer:
A is a function; B, C and D are not.
Step-by-step explanation:
In other words: Identify the sole function among these relationships.
A function maps any input onto exactly one output.
If a relationship maps any input onto more than one output, it is not a function.
Thus, we eliminate B, C and D. In B, for example, we have the inputs {1, 2, 3}, where the '1' has two y-values associated with it.
On the other hand, A has the domain {-1, 0, 1, 2}, and all four inputs have exactly one associated output.
Answer:
x=242/3
alternative form= 80 2/3, x=80.6
Step-by-step explanation:
3x-4y=242
substitute y = 0
3x-4x0=242
calculate the product
3x-0=242
remove 0
3x=242
divide both sides (by 3 in order to leave x by itself)
done
Answer:
<h2>-3 ; 3</h2>
Step-by-step explanation:
4x² - 36 = 0 ⇌ (2x)² - 6² = 0 ⇌ (2x - 6)(2x + 6) = 0 ⇌ 2x - 6 = 0 or 2x + 6 = 0
⇌ x = 3 or x = -3
