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fomenos
3 years ago
7

What is the solution of the system of linear equations? y = 3x - 2 y - 2 = x

Mathematics
1 answer:
iris [78.8K]3 years ago
6 0

Answer:

x = 2 y = 4

Step-by-step explanation:

y = 3x - 2

x = y - 2

Plug in the equation of x into the first equation and solve for y.

y = 3x - 2

y = 3(y - 2) - 2 Multiply out

y = 3y - 6 - 2

y = 3y - 8     Add 8 to each side

y + 8 = 3y - 8 + 8      8 cancels on the right

y + 8 = 3y          Subtract y from each side

y - y + 8 = 3y - y       The y on the left cancels

8 = 2y      Divide each side by 2

8/2 = 2y/2   2 on the right cancels because 2/2 = 1

8/2 = y

4 = y  

Now plug your answer into the 2nd equation given to solve for x.

x = y - 2

x = 4 - 2

x = 2

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Answer:

The quality control facility operates for 10 hours each day.

Step-by-step explanation:

The given function models the number of cars that are put through a quality control test each hour at a car production factory.

The given function is

c(t)= -t^2+8t+20

We need to find the number of hours does the quality control facility operate each day.

Rewrite the given function it factored form.

c(t)= -t^2+(10t-2t)+20

c(t)= (-t^2+10t)+(-2t+20)

Taking out the common factors from each parenthesis.

c(t)= -t(t-10)-2(t-10)

c(t)= (t-10)(-t-2)

c(t)=-(t-10)(t+2)

The factored form of given function is c(t)=-(t-10)(t+2).

Equate the function equal to 0 to find the x-intercept.

0=-(t-10)(t+2)

t-10=0\Rightarrow t=10

t+2=0\Rightarrow t=-2

Number of hours cannot be negative. So from t=0 to t=10 quality control facility operate the cars.

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7 0
3 years ago
Solve the following systems by Elimination
Alenkasestr [34]

Answer:

The solutions for both system of equations are as follows:

  1. (5,2)
  2. (2,-1)

Step-by-step explanation:

The first set of equations is:

4x+6y=32\\3x-6y=3\\

It can clearly be seen that the coefficients of y are already same in magnitude with different signs so we have to add both equations

So adding both equations, we get

4x+6y+3x-6y = 32+3\\7x = 35\\\frac{7x}{7} = \frac{35}{7}\\x = 5

Putting x=5 in equation 1

4(5)+6y = 32\\20+6y = 32\\6y = 32-20\\6y = 12\\\frac{6y}{6} = \frac{12}{6}\\y = 2

The solution is (5,2)

The second set of simultaneous equations is:

-3x+5y=-113x+7y=-1

We can see that the coefficients of x in both equations are same in magnitude with opposite signs so

Adding both equations

-3x+5y+3x+7y = -11-1\\12y = -12\\\frac{12y}{12} = \frac{-12}{12}\\y = -1

Putting y= -1 in first equation

-3x+5(-1)=-11\\-3x-5=-11\\-3x=-11+5\\-3x=-6\\\frac{-3x}{-3} = \frac{-6}{-3}\\x = 2

The solution is: (2,-1)

Hence,

The solutions for both system of equations are as follows:

  1. (5,2)
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3 years ago
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Archy [21]

Answer:

Opposite sides are corresponding (AB = DC).

Opposite angles are corresponding (D = B).

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Step-by-step explanation:

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A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears
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Answer:

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Step-by-step explanation:

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then,

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