I'm pretty sure that the answer is A
Hey!!
here is your answer >>>
1) 3x - 10 > 11
let's take this as 3x - 10 = 11
3x = 21
x = 7
So, The numbers of X are always more than 7
2) 9x + 2 < 5
9x + 2 = 5
9x = 3
x = 1÷2
The numbers of X are always less than 1 ÷ 2
3) 2x + 8 < 6
2x + 8 = 6
2x = 2
x = 1
The numbers of X are less than 1
4) 4x - 3 < 12
4x - 3 = 12
4x = 15
x = 15 ÷ 4
The numbers of X are less than 15 ÷ 4
5) 2 ( 9 + x ) > 20
2 ( 9 + x ) = 20
9 + x = 10
x = 1
The numbers of X are more than 1
We can solve the rest using this
Hope my answer helps!
Answer: choice 1 and 6
Step-by-step explanation:
just plug in 9 for every X making sure they equal each other.
