Answer
- 23.32°
- x=4637.16 feet
- y=1999.8 feet
- Explanation
Sketch a triangle ABC, where A is at the apex(top) and BC is the base.Let side AB=5050 feet and BC=6000feet.Drop a perpendicular line from A to BC at O to represent distance y and OB is distance x.
Point A = your location
Point B=First tower and Point C is the second tower.
To calculate the angle in degrees we use law of cosines,
2420²=5050²+6000²-(2)(5050)(6000)(cosB)
B=23.32° is the angle in question
Secondly, we find value of x
CosB=x/5050
X=4637.16feet, the position east of the tower
Thirdly, we calculate y
SinB=y/5050
0.39599=y/5050
y=1999.77
y=1999.8 feet , the position north of the tower
Answer:
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Hope I helped :]
