The domain of the function 3x² + 6x – 8 is a real number and the range of the function 3x² + 6x – 8 will be (-11, ∞).
<h3>What are domain and range?</h3>
The domain means all the possible values of the x and the range means all the possible values of the y.
The function is given below.
f(x) = 3x² + 6x – 8
The range of the function will be
f(x) = 3x² + 6x – 8
f(x) = 3x² + 6x + 3 – 11
f(x) = 3(x² + 2x + 1) – 11
f(x) = 3(x + 1)² – 11
Then the range of the function will be from -11 to infinity.
More about the domain and range link is given below.
brainly.com/question/12208715
No spaces? like t h i s? or like thiiiss??? is this bugging you ????
anyway
use elimination
multiply secn equation by -1
-3x-2y=-6
add to other equation
-3x-2y=-6
<u>4x+2y=10 +</u>
1x+0y=4
x=4
sub back to solve for y
3x+2y=6
3(4)+2y=6
12+2y=6
minus 12 both sides
2y=-6
divide 2
y=-3
(4,-3)
Answer:
the common ratio is either 2 or -2.
the sum of the first 7 terms is then either 765 or 255
Step-by-step explanation:
a geometric sequence or series of progression (these are the most common names for the same thing) means that every new term of the sequence is created by multiplying the previous term by a constant factor which is called the common ratio.
so,
a1
a2 = a1×f
a3 = a2×f = a1×f²
a4 = a3×f = a1×f³
the problem description here tells us
a3 = 4×a1
and from above we know a3 = a1×f².
so, f² = 4
and therefore the common ratio = f = 2 or -2 (we need to keep that in mind).
again, the problem description tells us
a2 + a4 = 30
a1×f + a1×f³ = 30
for f = 2
a1×2 + a1×2³ = 30
2a1 + 8a1 = 30
10a1 = 30
a1 = 3
for f = -2
a1×-2 + a1×(-2)³ = 30
-10a1 = 30
a1 = -3
the sum of the first n terms of a geometric sequence is
sn = a1×(1 - f^(n+1))/(1-f) for f <>1
so, for f = 2
s7 = 3×(1 - 2⁸)/(1-2) = 3×-255/-1 = 3×255 = 765
for f = -2
s7 = -3×(1 - (-2)⁸)/(1 - -2) = -3×(1-256)/3 = -3×-255/3 =
= -1×-255 = 255
Answer:
cut the box in half, 4*4=16
4*6= 24
16+24=40
40*13= 520$
Step-by-step explanation:
