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ioda
3 years ago
12

Which function increases at a faster rate on 0 to infinity, f(x) = x2 or g(x) = 2x?

Mathematics
2 answers:
Bond [772]3 years ago
6 0

Answer:

Sample Response: Using a table of values, the outputs of f(x) for whole numbers are 0, 1, 4, 9, 16, 25, 36, and so on. For the same input values, g(x) has outputs of 1, 2, 4, 8, 16, 32, and 64. Continuing to double the output each time results in larger outputs than those of f(x). The exponential function, g(x), has a constant multiplicative rate of change and will increase at a faster rate than the quadratic function.

Step-by-step explanation:

andreyandreev [35.5K]3 years ago
5 0

Answer:

the second one

Step-by-step explanation:

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A lottery game requires a person to select two upper case letters and three differentnon-zero digits. How many choices can the c
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A population of protozoa develops with a constant relative growth rate of 0.4964 per member per day. On day zero the population
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Answer:

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Step-by-step explanation:

This is an example of an exponential growth model. A quantity <em>y</em> that grows or decays at a rate proportional to its size fits in an equation of the form

\frac{dy}{dt}=ky

where k is a positive constant. Its solutions have the form

y=y_{0}e^{kt},

where y_{0} =y(0) is the initial value of y.

The population size can be calculated by using the below formula:

P(t)=P(0)e^{kt} where P(0) is the population on day zero.

Let t be the time in days,

We know from the information given that:

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  • The day zero (t = 0) the population size is 5 (P(0) = 5)

To find the population size after eight days

Substitute P(0) = 5, k=0.4964 in P(t)=P(0)e^{kt}

Then

P(t)=5e^{0.4964\cdot t}

Now we calculate P(t) when t = 8 days

P(8) = 5e^{0.4964\cdot 8}\\P(8) = 5e^{3.9712}\\e^{3.9712}=53.04815\dots \\P(8) = 5 \cdot 53.04815\dots\\P(8) = 265.24075\dots \approx 265

Therefore the population size after eight days is about 265

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