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Serhud [2]
3 years ago
11

What are the domain restrictions of a + 1 / a^2-5a-36?

Mathematics
1 answer:
velikii [3]3 years ago
3 0
All real numbers except -4 and 9.    

The domain of an expression is the range of all values for which the expression is defined. Looking at the expression, it will legal everywhere except when a^2 - 5a - 36 is equal to 0. Since that's a quadratic equation, we can use the quadratic formula to find where its value is 0, giving -4 and 9.    

Therefore the domain of the expression is, All real numbers except -4 and 9.
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3x+7y=76<br> 9y+5y=108<br> find x<br> find y
klemol [59]

In the given system of equations, the value of x is 7.334 and the value of y is 7.714

<h3>Solving system of linear equations</h3>

From the question, we are to solve the given system of linear equations

The given system of linear equations is

3x + 7y = 76               ------------ (1)

9y + 5y = 108             ------------ (2)

From equation (2), solve for y

9y+ 5y = 108

14y = 108

y = 108/14

y = 7.714

Substitute the value of x into equation (1), to determine the value of x

3x + 7y = 76

3x + 7(7.714) = 76

3x + 53.998 = 76

Subtract 53.998 from both sides of the equation

3x + 53.998 - 53.998  = 76 - 53.998

3x = 22.002

Divide both sides of the equation by 3

3x/3 = 22.002/3

x = 7.334

Therefore,

x = 7.334 and y = 7.714

Learn more on Solving system of linear equations here: brainly.com/question/13729904

#SPJ1

8 0
1 year ago
Consider the function f(x)=-3x^2 +7x -k. [3 Marks] a) For what values of k will the function have no zeros? b) For what values o
Anna35 [415]

Answer: a) k >4.08

b) k = 4.08

c) k<4.08

Step-by-step explanation:

Since we have given that

f(x)=-3x^2+7x-k

a) For what values of k will the function have no zeros?

It mean it has no real zeroes i.e. Discriminant < 0

As we know that

D=b^2-4ac

Here, a =-3

b = 7

c = -k

So, it becomes,

D

b) For what values of k will the function have one zero?

It means it has one real root i.e equal roots.

So, in this case, D = 0

So, it becomes,

D=b^2-4ac=0\\\\D=7^2-4\times -3\times -k=0\\\\49-12k=0\\\\49=12k\\\\k=\dfrac{49}{12}\\\\k=4.08

c) For what values of k will the function have two zeros?

It means it has two real roots.

In this case, D>0

So, it becomes,

D=7^2-4\times -3\times -k>0\\\\49-12k>0\\\\-12k>-49\\\\12k

Hence, a) k >4.08

b) k = 4.08

c) k<4.08

3 0
3 years ago
Hey everyone and good morning!!! take 30 points for free. Just have a great day!!
qaws [65]

Answer:

epic

Step-by-step explanation:

epic

5 0
3 years ago
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PLEASE HELP FAST simplify: sqrt 8 + 2 sqrt 15
Ket [755]

Answer:

2\sqrt{2} + 2\sqrt{15}

Step-by-step explanation:

\sqrt{8} = \sqrt{4}\sqrt{2} = 2\sqrt{2}

7 0
2 years ago
Indeed help with this plz
gizmo_the_mogwai [7]

Answer:

x=\frac{6-y-z}{3}

Step-by-step explanation:

5 0
3 years ago
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