Hey, i dont know what bantu jawab ya guys mean
Hello :
an equation is : y-5 = 0(x-3)....<span> perpendicular to the line x=4 ( parrallel to x-axis)
so ;
</span>y=5
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Note that if we add each side of the 2 equations, y will cancel out:
-12x-y+(17x+y)=6+4
5x=10
x=2
Substituting x=2 in either of the equations, we find the value of y.
Let's use the first equation:
-12x-y=6
-24-y=6
-y=24+6
-y=30, so y=-30.
Thus, the solution is (2, -30)
Answer: C
