Answer:
x-intercepts are (0, 0) and (-6, 0)
Step-by-step explanation:
equation of a parabola in vertex form: y = a(x - h)² + k
where (h, k) is the vertex
Substituting the given vertex (-3, -18) into the equation:
y = a(x + 3)² - 18
If the y-intercept is (0, 0) then substitute x=0 and y=0 into the equation and solve for a:
0 = a(0 + 3)² - 18
⇒ 0 = a(3)² - 18
⇒ 0 = 9a - 18
⇒ 9a = 18
⇒ a = 2
Therefore, y = 2(x + 3)² - 18
To find the x-intercepts, set the equation to 0 and solve for x:
2(x + 3)² - 18 = 0
Add 18 to both sides: 2(x + 3)² = 18
Divide both sides by 2: (x + 3)² = 9
Square root both sides: x + 3 = ±3
Subtract 3 from both sides: x = ±3 - 3
so x = 3 - 3 = 0
and x = -3 - 3 = -6
So x-intercepts are (0, 0) and (-6, 0)
f is the answer hope it helps
Answer:
-12
Step-by-step explanation:
Let the number be A
Given if you divide the sum of six and the number A by 3 , the result is 4 more than 1/4 of A
That’s
6+A/3 = 4+1/4 of A
6+A/3 = 4+1/4 x A
6+A/3 = 4+A/4
Cross multiply
4(6 + A) = 3(4 + A)
Distribute
4 x 6 + 4 x A = 3 x 4 + 3 x A
24 + 4A = 12 + 3A
Subtract 24 from both sides to eliminate 24 on the left side
24 - 24 + 4A = 12 - 24 + 3A
4A = -12 + 3A
Subtract 3A from both sides so the unknown can be on one side
4A - 3A = -12 + 3A - 3A
A = -12
Check
6+(-12)/3 = 4 +(-12)/4
6 -12/3 = 4 -12/4
-6/3 = -8/4
-2 = -2
Answer:
the correct for this question is be over the y-axis (x,y)=(-x,y)
