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scZoUnD [109]
3 years ago
12

There were 475 children at the baseball game on sunday .what is 475 rounded to the nearest ten

Mathematics
2 answers:
Ratling [72]3 years ago
8 0
480. Since the ones place is a five, you round up, so 475 becomes 480.
olasank [31]3 years ago
3 0
480 because 475 is nearest to 480 and 1,2,3,4 is under and 5,6,7,8,9 are over so it is to the next ten and if under it stays the same
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Equation of a straight line that passes through the points (4,2) and (2,3).?​
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7 0
3 years ago
This also 7th fgrade homework!!
harkovskaia [24]

Answer:

Down the left-hand column, the pattern is counting by 5's. Therefore, 5, 10, 15, 20, 25. Down the right-hand column, the pattern is counting by 4's. Therefore, 4, 8, 12, 16, 20. Thus, the ratios are:

5:4

10:8

15:12

20:16

25:20

In other words, the first line (5:4) is the base ratio. The second line multiplies the original values by 2, the third line by 3, the fourth line by 4, and the fifth line by 5.

6 0
4 years ago
Consider the functions f(x) = 2x + 1 and g(x) = x^2 − 10 What is the value of f[g(3)]?
HACTEHA [7]

Answer:

-1

Step-by-step explanation:

Tip: Remember to always start from the inside, which would be g(3), in this case.

The first step in solving this problem is to solve for g(3).

To accomplish this, you must substitute 3 for x into the given equation g(x) = x^2 - 10

  • g(3) = 3^2 - 10
  • g(3) = 9 - 10
  • g(3) = -1

The next step is to substitute the answer of g(3), -1, for x in the given equation f(x) = 2x + 1.

Because the equation is asking for f[g(3)], it becomes f(-1) because g(3) = -1.

  • f(-1) = 2(-1) + 1
  • f(-1) = -2 + 1
  • f(-1) = -1

Therefore, f[g(3)], or f(-1), equals -1

6 0
3 years ago
Find the function h(x) = f(x) ∘ g(x) if f(x) = x(2 - x) and g(x) = 3x.
skelet666 [1.2K]
H(x) = f(x) times g(x)
= (x(2-x)) * (3x)
= (2x-x^2)(3x)
= 6x-3x^3 ⇒ answer to your question
3 0
3 years ago
The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?
MaRussiya [10]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}

~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

3 0
1 year ago
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