9514 1404 393
Answer:
(x, y, z) = (2+44t, 2+14t, 7-20t)
Step-by-step explanation:
One way to write parametric equations for line L is ...
L = P + t·<em>v</em>
where P is the given point and <em>v</em> is the given direction vector. Using that form, we have ...
(x, y, z) = (2+44t, 2+14t, 7-20t)
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If you like, you can remove a common factor of 2 from the coefficients of t.
(x, y, z) = (2+22t, 2+7t, 7-10t)
True the circle is a congruent to the radius of an inscribed regular polygon inside the circle
Answer:
the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Step-by-step explanation:
since the volume of a cylinder is
V= π*R²*L → L =V/ (π*R²)
the cost function is
Cost = cost of side material * side area + cost of top and bottom material * top and bottom area
C = a* 2*π*R*L + b* 2*π*R²
replacing the value of L
C = a* 2*π*R* V/ (π*R²) + b* 2*π*R² = a* 2*V/R + b* 2*π*R²
then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then
dC/dR = -2*a*V/R² + 4*π*b*R = 0
4*π*b*R = 2*a*V/R²
R³ = a*V/(2*π*b)
R= ∛( a*V/(2*π*b))
replacing values
R= ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm
then
L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm
therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Answer:
My guess is 21
Step-by-step explanation:
