Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
Answer:
x-3=x+12
Step-by-step explanation:
because some number is x minus 3 would be x-3 is equal to so put an equal sign the product of the number x and 12
Answer:
48 months
Step-by-step explanation:
first take how much you need and add how much you want to leave, so 2500+500=3000. Then delete 600 from 3000, which will give you $2400. divide $2400 by 50 which gives you 48. it will take 48 months to get enough money to purchase a car at $2500 and leave $500 in the account.
Distance = √(x2-x1)² + (y2-y1)²
= √(2+1)² + (8-9)²
= √3² + (-1²)
= √ 3+1
= √4
= 2
In short, Your Answer would be 2 units
Hope this helps!
