output of the following code fragment that invokes Twist is:
1 14 3
Explanation:
In the function Twist(),two parameters are passed. First is passed by value and second is passed by reference. If a variable is passed by value then any change made by the function will not affect the original value of that variable but when a variable is passed by reference then any change made by the function will change the original value of that variable. When Twist() function invokes with a=3 and b=2 then value of c=3+2 i.e c=5, a=3*3 i.e. a=9 (value of "a" was 3 earlier) and and b=c+a i.e b=5+9. Here only "b"is passed by reference for variable "s" then any change in it's value will be reflected in the "s". That will update the value of "s" to 14.
Explanation:
Some of the most important features needed in a printer are:
- fast printing speed
- support wireless connectivity
- support colored/uncolored printing
- include improved text quality,
- improved photo printing capabilities
Based on market prices available on the Amazon website, a printer with the above capabilities start at a price range of <em>at least</em> $80.
Answer:
hope this helps. I am also a learner like you. Please cross check my explanation.
Explanation:
#include
#include
using namespace std;
int main()
{
int a[ ] = {0, 0, 0}; //array declared initializing a0=0, a1=0, a3=0
int* p = &a[1]; //pointer p is initialized it will be holding the address of a1 which means when p will be called it will point to whatever is present at the address a1, right now it hold 0.
int* q = &a[0]; //pointer q is initialized it will be holding the address of a0 which means when q will be called it will point to whatever is present at the address a0, right now it hold 0.
q=p; // now q is also pointing towards what p is pointing both holds the same address that is &a[1]
*q=1
; //&a[0] gets overwritten and now pointer q has integer 1......i am not sure abut this one
p = a; //p is now holding address of complete array a
*p=1; // a gets overwritten and now pointer q has integer 1......i am not sure abut this one
int*& r = p; //not sure
int** s = &q; s is a double pointer means it has more capacity of storage than single pointer and is now holding address of q
r = *s + 1; //not sure
s= &r; //explained above
**s = 1; //explained above
return 0;
}
As forensic evidence of suspected intrusions on a host system or network, indicators of compromise (IOCs) are used.
<h3>
What is indicators?</h3>
System administrators and information security (InfoSec) experts can identify malicious activity such as intrusion attempts using these artifacts. IOCs are used by security researchers to more thoroughly examine the methods and behaviour of a certain malware.
IOCs also offer useful threat intelligence that can be disseminated around the community to help organizations develop their incident response and remediation plans.
Some of these artifacts can be seen on the system's event logs, time-stamped entries, apps, and services. Various tools that monitor IOCs are also used by infosec experts and IT/system administrators to help mitigate, if not stop, breaches or assaults.
Therefore, As forensic evidence of suspected intrusions on a host system or network, indicators of compromise (IOCs) are used.
To learn more about indicators, refer to the link:
brainly.com/question/28093573
#SPJ1
Line 2 i looked it up on my phone
