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alukav5142 [94]
3 years ago
15

Warm Up ( 1. Solve forx. 2(x - 3) = 24

Mathematics
1 answer:
zvonat [6]3 years ago
7 0
Here’s the work for the answer


- Multiply 2 with X (invisible one before the x)

-Multiply 2 with 3

It should be 2x - 6 = 24

Add 6 to 24


2x = 30


Divide by 2 on both sides


X=15
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Answer:

52.2

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4 years ago
The parabola opens:<br> O left<br> O up<br> O down<br> O right
sattari [20]

The given parabola will open; Down

<h3>How to interpret a parabola curve?</h3>

In parabolic curves, if the leading coefficient is greater than zero, the parabola opens upward, and if the leading coefficient is less than zero, the parabola opens downward.

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Musya8 [376]

Answer:

We get t= 7.22 and t=0.28

The correct options are Option A and Option G

Step-by-step explanation:

The height h of toy rocket at time t seconds after  launch is given by the equation h(t) = -16t^2 + 120t + 8

We need to find how many seconds  until the rocket is 40 feet?

We are given height of rocket h(t) = 40 feet

and we need to find time t

Using the equation h(t) = -16t^2 + 120t + 8 we can find time t

We have h(t)=40

h(t) = -16t^2 + 120t + 8\\Put\:h(t)=40\\40= -16t^2 + 120t + 8\\16t^2-120t-8+40=0\\16t^2-120t+32=0

Now, we will solve the quadratic equation using quadratic formula: t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

We have a =16, b=-120 and c=32

Putting values and finding t

t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\t=\frac{-(-120)\pm\sqrt{(-120)^2-4(16)(32)}}{2(16)}\\t=\frac{120\pm\sqrt{14400-2048}}{32}\\t=\frac{120\pm\sqrt{12352}}{32}\\t=\frac{120\pm111.12}{32}\\t=\frac{120+111.12}{32}, t=\frac{120-111.12}{32}\\t=7.22\:,\:t=0.28

So, we get t= 7.22 and t=0.28

The correct options are Option A and Option G

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