1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ostrovityanka [42]
2 years ago
14

What is the average group numbers for 85,92,84,85,96,95

Mathematics
1 answer:
laiz [17]2 years ago
5 0
To find the average, add all numbers together and divide by the amount of numbers there are

(85 + 92 + 84 + 85 + 96 + 95)/6 = 537/6 = 89.5 

you're answer is 89.5 as average

hope this helps
You might be interested in
Write the domain and range of the graph below…
saveliy_v [14]

Answer:

Range:-4 is less then Y is less then 9. Domain: -5 is less then x is less then 4

Step-by-step explanation:

Look at where the lines end. That will help you find where the domain and ranges are.

5 0
2 years ago
How do you solve this
brilliants [131]
First, ask somebody else like your teacher, also use your brain

5 0
2 years ago
All the dimensions of a pentagon were multiplied by the same factor, and area of the figure changed by a factor if 25. By what f
Oksana_A [137]

Answer:

50

Step-by-step explanation:

You add the 25 + another 25 and that adds up to 50. Hope this helps!

4 0
2 years ago
Express the fractions 1/2, 3/16, and 7/8 with an LCD
Ket [755]
<span>Least Common Denominator (LCD) is the least number which all the denominators can divide without remainder. The given denominators are 2, 16 and 8. The least number 2, 16 and 8 will divide without remainder is 16. Therefore, to express the fractions 1/2, 3/12, and 7/8 with an LCD, we multiply both the numerator and the denominator of each of the fractions with a common factor that makes the denominator to be 16. Therefore, 1/2, 3/16 and 7/8 expressed with an LCD are (1 x 8) / (2 x 8), 3/16, (7 x 2) / (8 x 2) = 8/16, 3/16, and 14/16.</span>
5 0
3 years ago
A bag contains three marbles, eight blue marbles and nine red marbles. If the marbles are picked at random, what is the probabil
Phoenix [80]

The probability of obtaining two blue marbles without replacement is equal to 0.15.

We are given that:

The number of yellow marbles = 3

Number of red marbles = 9

Number of Blue marbles = 8

Total marbles = 3 + 9 + 8

Total marbles = 20

Now, we have to calculate the probability of obtaining two blue marbles without replacement.

The probability will be:

P( obtaining two blue marbles without replacement )  = 8 / 20 × 7 / 19

P( obtaining two blue marbles without replacement )  = 56 / 380

P( obtaining two blue marbles without replacement )  = 0.15

Therefore, the probability of obtaining two blue marbles without replacement is equal to 0.15.

Learn more about probability here:

brainly.com/question/24756209

#SPJ9

5 0
1 year ago
Other questions:
  • Jodie bought some shirt for $6. Marge bought soñé shirts por $8 each. The girls spent the same amount of money on shirt. What is
    7·1 answer
  • Bill wants to save up to buy a new watch which costs $235. If he already has $75 and he saves $8 each week, how many weeks will
    15·2 answers
  • 21 students went on an exchange program to hong kong. There were 11 more women than men. How many woman are there?
    15·1 answer
  • Circle A has a center at the origin and a point M located on the circle at (1,0). Circle B has a center at (-2,1) and point N lo
    6·1 answer
  • Which item below would be least expensive, with sales tax?
    12·1 answer
  • 12/24 reduced fraction
    9·2 answers
  • The perimeter of a square garden is 52 feet. What is the length of each side?
    8·1 answer
  • Derrick's Dog Sitting and Darlene's Dog Sitting are competing for new business. Derrick's Dog Sitting charges $12 plus $7 per ho
    9·2 answers
  • 11. Robby walks 4 blocks east and 3 blocks north to get to school from his house, as
    11·1 answer
  • Reflect line AB over the x- axis.
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!