SOLUTION:
PQR is a right-angle triangle.
Therefore, to solve this problem, we will use Pythagoras theorem which is only applicable to right-angle triangles.
Pythagoras theorem is as displayed below:
a^2 + b^2 = c^2
Where c = hypotenuse of right-angle triangle
Where a and b = other two sides of right-angle triangle
Now we will simply substitute the values from the problem into Pythagoras theorem in order to obtain the length of QR.
c = PQ = 16cm
a = PR = 8cm
b = QR = ?
a^2 + b^2 = c^2
( 8 )^2 + b^2 = ( 16 )^2
64 + b^2 = 256
b^2 = 256 - 64
b^2 = 192
b = square root of ( 192 )
b = 13.8564...
b = 13.86 ( to 2 decimal places )
FINAL ANSWER:
Therefore, the length of QR is 13.86 centimetres to 2 decimal places.
Hope this helps! :)
Have a lovely day! <3
Answer:
x = 77, x = -77
Step-by-step explanation:
|x| – 17 = 60
Add 17 to each side
|x| – 17+17 = 60+17
|x| = 77
The absolute value equation has two solutions, one positive and one negative
x = 77, x = -77
I think multiplication but I’m not sure sorry
we are given the expression csc (2 pi / 3 ) and is asked to evaluate the expression. According to the trigonometric identities, the inverse of cosecant (CSC) is sine (sin) function. hence using the calculator in radians mode, sin 2pi/3 is equal to 2/sqrt 3. Taking the reciprocal of the answer, the final answer is 2 sqrt3 over 3.
