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2 years ago

10

Can someone help me please

1 answer:

Arte-miy333 [17]2 years ago

6 0

Answer:

The answer is 4

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27. The altitude BD to the base AC of isosceles ABC has a length of 12. If AC = 10,

Vsevolod [243]

The answer is: 36

Because, bisecting the base of the triangle gives of two segments of five. This forms two triangles with base of 5 and altitude (in this case height) of 12. There exists a special pythagorean triplet triangled named 5-12-13 meaning if you have a right triangle with two of these sides then the unknown side is the number left out. In this case, the altitude forms a right angle on the base which allows the sides of the big isocs. triangle to be 13 giving us 13 + 13 + 10 to be the perimeter = 36.

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3 years ago

At the music store Katelyn bought 2 packs of

kirza4 [7]

For one pack of guitar strings, it cost $14.00

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3 years ago

Find the surface area of the rectangular prism. 8 yd 4 yd 5 yd Answer: yd? Submit Answer

Rashid [163]

The area of the circle is 18

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3 years ago

Shay mal e 8 2/3 cups of snacks mix she puts all the snack mix into plastic bags she puts 1/3 cup of the snack mix in each bag h

AnnyKZ [126]

Answer:

She needs 26 plastic bags.

Step-by-step explanation:

Given:

Amount of cups of snacks mix = 8 2/3

Rewriting 8 2/3 we get,

Amount of snacks mix = $\frac{26}{3}$

Number of Cups in each bag = $\frac{1}{3}$

She puts all the snacks mix in plastic bags

We need to find the number of plastic bags required to put all the snacks mix

Let number of plastic bag be x.

hence we can say that Number of Cups in each bag multiplied by number of plastic bag is equal to Amount of snacks mix.

$\frac{1}{3}x=\frac{26}{3}\\\\x= \frac{26\times3}{3\times1} =26$

Hence total number of plastic bags she needs is 26.

6 0

3 years ago

13x=-21-6y and -8x=36+6y

IgorLugansk [536]

Answer:

$x=3\\y=-10$

Step-by-step explanation:

$13x=-21-6y\\-8x=36+6y$

Let's take one of the equations and solve for x. I'll take the first one.

$13x=-21-6y$

Divide by 13.

$x=\frac{-21-6y}{13}$

Now replace x in the second equation.

$-8x=36+6y\\-8(\frac{-21-6y}{13} )=36+6y$

Distribute -8

$\frac{168+48y}{13}=36+6y$

Break down the fraction.

$\frac{168}{13}+\frac{48}{13}y=36+6y$

Subtract $\frac{168}{13}$

$\frac{48}{13}y=36+6y-\frac{168}{13}$

Subtract 6y

$\frac{48}{13}y-6y=36-\frac{168}{13}$

Combine like terms;

$\frac{48-13*6}{13}y=\frac{36*13-168}{13}$

Solve;

$\frac{48-78}{13}y=\frac{468-168}{13}$

Keep solving;

$\frac{-30}{13}y=\frac{300}{13}$

Multiply by the negative reciprocal of the fraction next to y.

$(-\frac{13}{30} )\frac{-30}{13}y=\frac{300}{13}(-\frac{13}{30} )$

On the right side; 13 and 13 become 1. 300/30 = 30/3 = 10

$y=-10$

After having found y, replace it in any of the equations to find x.

$13x=-21-6y\\13x=-21-6(-10)\\13x=-21+60\\13x=39\\x=\frac{39}{13}\\ x=3$

6 0

3 years ago

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