The graph of f ′ (x), the derivative of f of x, is continuous for all x and consists of five line segments as shown below. Given
f (–3) = 6, find the absolute maximum value of f (x) over the interval [–3, 0].
Graph of line segments increasing from x equals negative 4 to x equals negative 3, decreasing from x equals negative 3 to x equals 0, increasing from x equals 0 to x equals 3, constant from x equals 2 to x equals 4 and decreases from x equals 4 to x equals 5. x intercepts at x equals negative 4, x equals 0, x equals 5.
3
4.5
6
10.5
Graph of line segments increasing from x equals negative 4 to x equals negative 3, decreasing from x equals negative 3 to x equals 0, increasing from x equals 0 to x equals 3, constant from x equals 2 to x equals 4 and decreases from x equals 4 to x equals 5. x intercepts at x equals negative 4, x equals 0, x equals 5.
3
4.5
6
10.5
1 answer:
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Answer:
Step-by-step explanation:
Line is passing through the point and has slope (m) = - 9
General equation of line in point slope form is given as:
Therefore
This is the required equation of line in point slope form.