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nika2105 [10]
3 years ago
10

What is the distributive property to expand the algebraic expression.5(2f - 6g)

Mathematics
1 answer:
Gnoma [55]3 years ago
7 0

Answer:

10f-30g

Step-by-step explanation:

we have:

5(2f - 6g)

we apply distributive property:

5(2f - 6g)

5*2f+5*(-6g)

finally we have:

10f-30g

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A computer software vendor claims that a new version of its operating system will crash fewer than 10 times per year on average.
Oksana_A [137]

Answer:

Step-by-step explanation:

The hypothesis is written as follows

For the null hypothesis,

µd ≤ 10

For the alternative hypothesis,

µ > 10

This is a right tailed test

Since no population standard deviation is given, the distribution is a student's t.

Since n = 97

Degrees of freedom, df = n - 1 = 97 - 1 = 96

t = (x - µ)/(s/√n)

Where

x = sample mean = 8.9

µ = population mean = 10

s = samples standard deviation = 3.6

t = (8.9 - 10)/(3.6/√97) = - 3

We would determine the p value using the t test calculator. It becomes

p = 0.00172

Since alpha, 0.01 > than the p value, 0.00172, then we would reject the null hypothesis. Therefore, At a 1% level of significance, there is enough evidence that the data do not support the vendor’s claim.

3 0
3 years ago
Approximate the change in the volume of a sphere when its radius changes from r = 30 ft to r=10.1 ft [v(r)=4/3Ï€r^3]. When r cha
ella [17]

Answer: ∆V for r = 10.1 to 10ft

∆V = 40πft^3 = 125.7ft^3

Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________

[v(r)=4/3Ï€r^3].

Step-by-step explanation:

Volume of a sphere is given by;

V = 4/3πr^3

Where r is the radius.

Change in Volume with respect to change in radius of a sphere is given by;

dV/dr = 4πr^2

V'(r) = 4πr^2

V'(10) = 400π

V'(10.1) - V'(10) ~= 0.1(400π) = 40π

Therefore change in Volume from r = 10 to 10.1 is

= 40πft^3

Of by direct substitution

∆V = 4/3π(R^3 - r^3)

Where R = 10.1ft and r = 10ft

∆V = 4/3π(10.1^3 - 10^3)

∆V = 40.4π ~= 40πft^3

And for R = 30ft to r = 10.1ft

∆V = 4/3π(30^3 - 10.1^3)

∆V = 34626.3πft^3

3 0
3 years ago
Please help me ASAP yall!!!
ASHA 777 [7]

Answer:

60

Step-by-step explanation:

<C+<D = 180 since they form a straight line

5x+20 +3x = 180

8x+20 = 180

Subtract 20 from each side

8x+20-20 = 180-20

8x = 160

Divide by 8

8x/8 = 160/8

x = 20

We want to find angle D

<D = 3x= 3*20 = 60

8 0
3 years ago
Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
3 years ago
Which expression is equal to 4-6
frez [133]

-1-1 or 2-4 or 3-5 or 6-8 or 7-9 or 8-10

6 0
2 years ago
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