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grigory [225]
3 years ago
12

Pls help me with this I’ll really appreciate it

Mathematics
1 answer:
nlexa [21]3 years ago
3 0

Answer:

factor completely to get 4x squared plus 8x minus 3 like how x plus 2 and x plus 8 are. Look on KhanAcademy

Step-by-step explanation:

You might be interested in
If RS = 17, ST = x + 6, and RT = 3x - 5, What is ST.
tigry1 [53]

Answer:

ST = 20

Step-by-step explanation:

Line segment RS and segment ST must add up to line segment RT

Step 1: Define

RS = 17

ST = x + 6

RT = 3x - 5

Step 2: Set up equation

mRS + mST = mRT

17 + x + 6 = 3x - 5

Step 3: Solve for <em>x</em>

x + 23 = 3x - 5

23 = 2x - 5

28 = 2x

x = 14

Step 3: Find mST

ST = x + 6

ST = 14 + 6

ST = 20

3 0
3 years ago
If the the area of a bedroom is 90 square feet what is the length and width
Anna [14]
30 x 30........................
6 0
2 years ago
What is the slope of the line passing through (-5,2) and (1,8)
nikdorinn [45]

Answer:

go to slope calclculator

Step-by-step explanation:

6 0
2 years ago
Can you help me with number 3? Please!!!!
Fantom [35]

Answer:

D

Step-by-step explanation:

Take it step by step.

The area of a rectangle is width times length.

We know the length is 7 since it's given, and we can find the width by adding shared sides of the square and triangle.

So the width is 10 + 14 or 24

That means the area of the rectangle is 7 * 24

The area of the second rectangle is 12 * 14, since they are both given.

Finally, the area of the triangle is 1/2 of the base times height and we can find the height by looking at the shared side and using the definition of a rectangle.

So the area of the triangle is 1/2 of 10 * 12.

3 0
3 years ago
Factor the GCF: −6x4y5 − 15x3y2 + 9x2y3 (5 points)
nadezda [96]
*Hint: Before you try to factor anything, you try to see if they have a common factor.

Since -3 is a common factor, everything is divided by -3.

-6x^4y^5 - 15x^3y^2 + 9x^2y^3
-3(2x^4y^5 + 5x^3y^2 - 3x^2y^3)

Since you can still divide by x^2y^2, you do so.
-3x^2y^2 (2x^2y^3 + 5x - 3y)
7 0
3 years ago
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