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3 years ago

Martha's weight is 75kg. Her weight increased by 3%. What is her new weight?

Mathematics

2 answers:

Iteru [2.4K]3 years ago

5 0

Top one is correct (mark him brainiest)

Brums [2.3K]3 years ago

3 0

Martha’s new weight is 77.25. 3% of 75 is 2.25 and you can find that by multiplying 75 by .03 and adding that number to 75. hope this helps!

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The volume of a cube is 27 cubic inches. What is the length of one edge of the cube?

hjlf

The volume for any cube is length x width x height,
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y x y x y = 27
y = 3
so each side will be 3 inches

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3 years ago

(a+b+c)-a3-b3-c3=3 (a+b)(b+c)(c+a)

Valentin [98]

1.a3,b3 and c3 must be 2 digit number.
2. a3 must be greater than all the other number.
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3 years ago

If point C is between points A and B, then AC + CB = ___.

mario62 [17]

The correct answer is: AB

Explanation:

There are two ways you can understand this:

1. By drawing:

A ------ C ------B

As you can see the point C is between A and point B, hence AC + CB = AB. One thing to remember here is that point C can be anywhere between the point A and B, in that case, the answer will remain be the same AB. For instance:

A --- C -------------B

Again, AC + CB = AB.

2. By inference:

If the point C is between points A and B, it means that the point C lies on the line AB; if point C were not on the line AB, it will not be between points A and B. Hence, you can infer that AB is a line and point C lies on it and is between points A and B.

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3 years ago

Read 2 more answers

A coat cost $ 131.61 with 9.5% sales tax

marysya [2.9K]

Calculating Total Cost. Multiply the cost of an item or service by the sales tax in order to find out the total cost. The equation looks like this: Item or service cost x sales tax (in decimal form) = total sales tax. Add the total sales tax to the Item or service cost to get your total cost. Multiply retail price by tax rate

Let's say you're buying a $100 item with a sales tax of 5%. Your math would be simply: [cost of the item] x [percentage as a decimal] = [sales tax]. That's $100 x .

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3 years ago

An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de

Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

$P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721$

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

$P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have:

$P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528$

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

$P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have

$P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453$

The sum of the probabilities is

$P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981$

8 0

3 years ago