Answer:
m∠A = 50°
m∠B = 70°
m∠C = 60°
Step-by-step explanation:
Determine the measure of angle A, B, and C in triangle ABC. If m∠A=(x-10)°,m∠B=(2x-50)°,and m∠C=x°
In a Triangle, the sum of the interior angles of a triangle = 180°
Step 1
We solve for x
Hence:
m∠A + m∠B + m∠C= 180°
(x-10)°+ (2x-50)°+ x° = 180°
x - 10 + 2x - 50 + x = 180°
4x - 60 = 180°
4x = 180° + 60°
4x = 240°
x = 240°/4
x = 60°
Step 2
Solving for each measure
x = 60°
m∠A=(x-10)°
= 60° - 10°
= 50°
m∠B=(2x-50)°
= 2(60)° - 50°
= 120° - 50°
= 70°
m∠C=x°
= 60°
Dividing (3x^2-2x) by x gives out 3x-2
When you divide two fractions, you're actually multiplying one of them by the reciprocal of the other. First, find the reciprocal of the second fraction by flipping it upside down. Then, multiply it by the first fraction. (Numerator x numerator and denominator x denominator)
÷
Replace the second fraction with it's reciprocal
x
Multiply (-7 x 3 and 12 x 2)
Both 21 and 24 are divisible by three, so divide them by 3
Answer:
45 degrees
Step-by-step explanation:
AOB = 140°
and an the angle bisector(OC) is a line which will divide AOB into 2 equal angles
which is 140÷2= 70
and if AOD = 25 then COD= 70-25
= 45 degrees
hope it helps
