If the triangle is a right triangle, the pythagorean theorem would work
since it doesn’t, the triangle is NOT A RIGHT TRIANGLE

(see attached pic for work :))

6 0

3 years ago

Find the surface area of the cone to the nearest tenth.

vfiekz [6]

Surface area = base area + side area

= pi * 7^2 + pi * 7 * 27 = 238pi = 747.7 cm^2

7 0

4 years ago

Read 2 more answers

I need help. this is the problem x^2/3+10=7x^1/3

Arlecino [84]

$\it x^{\frac{2}{3}}+10=7x^{\frac{1}{3}} \Leftrightarrow (x^{\frac{1}{3}})^2-7x^{\frac{1}
 {3}} +10=0 
\\\;\\
We\ note\ x^{\frac{1}{3}} =t \ \ and \ the \ equation \ will \ be:
\\\;\\
t^2-7t+10 = 0 \Leftrightarrow t^2 -2t-5t+10=0 \Leftrightarrow t(t-2) -5(t-2)=0$

$\it \Leftrightarrow (t-2)(t-5)=0 
\\\;\\
t-2=0 \Rightarrow t=2 \Rightarrow x^{\frac{1}{3}}=2 \Rightarrow (x^{\frac{1}{3}})^3 =2^3 \Rightarrow x = 8
\\\;\\
t-5=0 \Rightarrow t=5 \Rightarrow x^{\frac{1}{3}}= 5 \Rightarrow (x^{\frac{1}{3}})^3 = 5^3 \Rightarrow x = 125$

S = {8; 125}

7 0

4 years ago

I can't find the volume

sp2606 [1]

Answer:

8π(2.5)^2

Step-by-step explanation:

volume = π * r^2 * h

v = π * (2.5)^2 * 8

7 0

3 years ago