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nadya68 [22]
3 years ago
10

Write a for loop that prints the odd integers 11 through 121 inclusive, separated by spaces.

Computers and Technology
1 answer:
mixas84 [53]3 years ago
4 0
The code for the above problem is:
<span>/* package whatever; // don't place package name! */ 

import java.util.*;
import java.lang.*;
import java.io.*; 

/* Name of the class has to be "Main" only if the class is public. */

class Ideone{ public static void main (String[] args) throws java.lang.Exception 
{ 
 for(int i=11; i<=121; i=i+2){
   System.out.print(i); System.out.print(" "); 
 } 
}<span>}

I hope this is the answer that you were looking for. </span></span>
You might be interested in
The range A2:B4 has how many cells?<br><br> Answers:<br> 2,4,6,8
mylen [45]
6 cells because you have to drag and it becomes six cells .

8 0
4 years ago
Read 2 more answers
and assuming main memory is initially unloaded, show the page faulting behavior using the following page replacement policies. h
Svet_ta [14]

FIFO

// C++ implementation of FIFO page replacement

// in Operating Systems.

#include<bits/stdc++.h>

using namespace std;

// Function to find page faults using FIFO

int pageFaults(int pages[], int n, int capacity)

{

   // To represent set of current pages. We use

   // an unordered_set so that we quickly check

   // if a page is present in set or not

   unordered_set<int> s;

   // To store the pages in FIFO manner

   queue<int> indexes;

   // Start from initial page

   int page_faults = 0;

   for (int i=0; i<n; i++)

   {

       // Check if the set can hold more pages

       if (s.size() < capacity)

       {

           // Insert it into set if not present

           // already which represents page fault

           if (s.find(pages[i])==s.end())

           {

               // Insert the current page into the set

               s.insert(pages[i]);

               // increment page fault

               page_faults++;

               // Push the current page into the queue

               indexes.push(pages[i]);

           }

       }

       // If the set is full then need to perform FIFO

       // i.e. remove the first page of the queue from

       // set and queue both and insert the current page

       else

       {

           // Check if current page is not already

           // present in the set

           if (s.find(pages[i]) == s.end())

           {

               // Store the first page in the

               // queue to be used to find and

               // erase the page from the set

               int val = indexes.front();

               

               // Pop the first page from the queue

               indexes.pop();

               // Remove the indexes page from the set

               s.erase(val);

               // insert the current page in the set

               s.insert(pages[i]);

               // push the current page into

               // the queue

               indexes.push(pages[i]);

               // Increment page faults

               page_faults++;

           }

       }

   }

   return page_faults;

}

// Driver code

int main()

{

   int pages[] = {7, 0, 1, 2, 0, 3, 0, 4,

               2, 3, 0, 3, 2};

   int n = sizeof(pages)/sizeof(pages[0]);

   int capacity = 4;

   cout << pageFaults(pages, n, capacity);

   return 0;

}

LRU

//C++ implementation of above algorithm

#include<bits/stdc++.h>

using namespace std;

// Function to find page faults using indexes

int pageFaults(int pages[], int n, int capacity)

{

   // To represent set of current pages. We use

   // an unordered_set so that we quickly check

   // if a page is present in set or not

   unordered_set<int> s;

   // To store least recently used indexes

   // of pages.

   unordered_map<int, int> indexes;

   // Start from initial page

   int page_faults = 0;

   for (int i=0; i<n; i++)

   {

       // Check if the set can hold more pages

       if (s.size() < capacity)

       {

           // Insert it into set if not present

           // already which represents page fault

           if (s.find(pages[i])==s.end())

           {

               s.insert(pages[i]);

               // increment page fault

               page_faults++;

           }

           // Store the recently used index of

           // each page

           indexes[pages[i]] = i;

       }

       // If the set is full then need to perform lru

       // i.e. remove the least recently used page

       // and insert the current page

       else

       {

           // Check if current page is not already

           // present in the set

           if (s.find(pages[i]) == s.end())

           {

               // Find the least recently used pages

               // that is present in the set

               int lru = INT_MAX, val;

               for (auto it=s.begin(); it!=s.end(); it++)

               {

                   if (indexes[*it] < lru)

                   {

                       lru = indexes[*it];

                       val = *it;

                   }

               }

               // Remove the indexes page

               s.erase(val);

               // insert the current page

               s.insert(pages[i]);

               // Increment page faults

               page_faults++;

           }

           // Update the current page index

           indexes[pages[i]] = i;

       }

   }

   return page_faults;

}

// Driver code

int main()

{

   int pages[] = {7, 0, 1, 2, 0, 3, 0, 4, 2, 3, 0, 3, 2};

   int n = sizeof(pages)/sizeof(pages[0]);

   int capacity = 4;

   cout << pageFaults(pages, n, capacity);

   return 0;

}

You can learn more about this at:

brainly.com/question/13013958#SPJ4

4 0
1 year ago
An attacker is trying to redirect the traffic of a small office. That office is using their own mail server, DNS server and NTP
yaroslaw [1]

Answer:

The correct option to the following question is option (A) DNS spoofing.

Explanation:

(Domain Name System)DNS spoofing is also known as the Domain Name System Poisoning.

DNS spoofing referred to as the DNS server is the record of 'spoofed' or redirect the traffic. This redirections of the traffic assents the hackers to steal data, spread malware, etc.

<u>DNS works out by using various functions are</u>:

  • 'Compromising the DNS server'
  • 'DNS cache poisoning'
  • 'Implementing the Metropolitan Area Network in Middle Attack'.
5 0
4 years ago
Describe FIVE significant advantages of web-based applications for an organisation.
masya89 [10]

Answer

There are a lot of advantages of web based applications.

Explanation:

Below are the advantages:

  1. Web based applications can be accessed from device that is connected to the device.
  2. No physical software required to download, install, update or manage which saves a lot of administration work for large companies.
  3. Web based software is compatible with any device or platform. The software is delivered through a browser of the users' choice.
  4. Mobile device applications allow for access to the software when out of the office.
  5. Direct access to latest information for Employees where every they are located.

Apart from these, there are lot more benefits, like quick and easy updates, centralized data where data is secure and easy to backup.  We can reach anybody, anywhere in the world.

Business costs are drastically reduced by spending less time talking to customers over the phone.

Online training can be finished at user's own time and risk.

It's available 24 hours a day, 7 days a week

The software is always up-to-date

8 0
3 years ago
Plzz helps me with hw
IceJOKER [234]

Answer:

1. not statistical

2. statistical

3. statistical

4. not statistical

5. statistical

6. not statistical

7. statistical

Explanation:

The statistical can compare more then 1 thing to make it reasonable.

4 0
4 years ago
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