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3 years ago

Please Help will give points PLEASE!!!!

Mathematics

1 answer:

Paul [167]3 years ago

8 0

Answer:

I to 16

Step-by-step explanation:

The first point was put on one and the last was on 16

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Han ran 10 meters in 2.7 seconds.Priya ran 10 meters in 2.4 seconds.Who is faster?

ololo11 [35]

Answer:

Praiya lol

Step-by-step explanation:

Han ran 10 meters in 2.7 secs. Priya ran 10 in 2.4 secs. Do the math

4 0

3 years ago

Read 2 more answers

Select all the expressions that are equivalent to 9 + 7x – 3y. 9 + 7x + 3y 9 – 7x – 3y 9 – 7x + 3y 9 + 7x + (–3y) 9 – (–7)x – 3y

bulgar [2K]

0^9 +7x+189yx−3y

+7x−3y

+7x+3y

−7x−3y

−7x+3y

+7x+189yx−3y

2 Collect like terms.

{o}^{9}+(7x+7x-7x-7x+7x)+(-3{y}^{9}+3{y}^{9}-3{y}^{9}+3{y}^{9})+189yx-3y

+(7x+7x−7x−7x+7x)+(−3y

+3y

−3y

+3y

)+189yx−3y

3 Simplify.

{o}^{9}+7x+189yx-3y

+7x+189yx−3y

6 0

3 years ago

Are the triangles congruent if they are which theorem and why?

leonid [27]

Yes the sides are equal to each other

7 0

3 years ago

Is this an example of a horizontal asymptote?

8_murik_8 [283]

Answer:

Step-by-step explanation:

Hi there,

The graph indicated is showing a horizontal asymptote. In fact, it is showing both a horizontal and a <em>vertical </em>asymptote.

To tell which type it is, notice where the graph "shoots off" and almost forms an imaginary straight line in one direction. Using this logic, the horizontal asymptote will be exactly horizontal, parallel to x-axis, and vertical asymptote will be exactly vertical, parallel to y-axis.

With this graph, we notice the horizontal asymptote is at y=0, where the x-axis is. The vertical asymptote is bit more difficult to determine graphically, but can definitely say it is past x=-10. We could determine it if we had the function, but that is not necessary for this question.

Study well, and persevere. If you liked this solution, leave a Thanks or give a rating!

thanks,

6 0

3 years ago

PART TWO MATH TEST :)<br><br> Please Help! I will give brainliest and donuts <33

ra1l [238]

Hey there,

Question #1

The answer would be in the attachment below.
_____________________________________________________________

Question #2

The answer would be in the attachment below.
_____________________________________________________________

Question #3

The answer would be in the attachment below.
_____________________________________________________________

Question 4#

The last one was kind of tricky. But, as I saw this attachment, I noticed on how the rectangle was actually 3/4 on the base and for the height, it was 1/2. So by doing this,we need to find the area, and we would multiply these both. 1/2 x 3/4 = 3/8 but by looking at your options, those are not simplified so . . .your answer would be 6/16 because 3x2=6 & 8x2=16.
_____________________________________________________________

I really hope this can help you Amanda.

Have a great day! =)

~Jurgen

6 0

4 years ago