All categories

2 years ago

Is anyone good at Simplifying Radical Expressions?

1 answer:

3 0

All you really have to do is find the prime factorization of the term. And for every pair of like factors you can move that term outside of the radical sign (for square roots) If you were doing cube roots you would need to find threesomes of factors... for example..

20^(1/2)

pf 20=2*2*5 so you have two twos so you can simplify to 2(5)^(1/2)

108^(1/3)

pf 108=2*2*3*3*3 so you have 3^3 so you can simplify to 3(4)^(1/3)

You might be interested in

Kim is trying to save at least $450. She has already saved $75. She can babysit for $5 an hour. How many hours does Kim need to

larisa [96]

Answer:

70 hours.

Step-by-step explanation:

you need to subtract 450 from 75 which tells you you need 350 more dollars then you need to do 5x70 which gives you 350.

7 0

2 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

2 years ago

Which rule describes the function in the graph below?

m_a_m_a [10]

The function that models the graph is given as: $f(x)=\left \{ {{-\frac{1}{3}x+\frac{4}{3} \ \ -8 < x < 2} \atop {-x^2+6\ \ -2 < x < 0}} \atop {6\ \ 0 < x < 4}, \ \ x+2\ \ 4 < x < 7 \right.$

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

The equation shown in the graph represents a piecewise function. Hence:

From the line through the point (-8, 4) and (-2, 2), the equation is f(x) = -(1/3)x + 4/3

From the curve through the point (-2, 2) and (0, 6), the equation is f(x) = -x² + 6

From the line through the point (0, 6) and (4, 6), the equation is f(x) = -6

From the line through the point (4, 6) and (7, 9), the equation is f(x) = x + 2

The function that models the graph is given as: $f(x)=\left \{ {{-\frac{1}{3}x+\frac{4}{3} \ \ -8 < x < 2} \atop {-x^2+6\ \ -2 < x < 0}} \atop {6\ \ 0 < x < 4}, \ \ x+2\ \ 4 < x < 7 \right.$

Find out more on equation at: brainly.com/question/2972832

#SPJ1

3 0

1 year ago

Antonio uses this redipe to make a fruit smoothie. Fruit Sinoothie eup orange juice cup Yogurt Nino no Cup Strawberries eup blue

ozzi

Answer:

I think it's B.

Step-by-step explanation:

Hope this helps. :)

7 0

1 year ago

What is the length of s?

Serggg [28]

Answer:

Step-by-step explanation:

We will use trigonometry to solve this problem.

We see that the side provided is the hypotenuse and the side we are looking for is opposite to the angle provided. Thus, we will use sin since sin uses opposite/hypotenuse.

Now we solve.

sin45 = x/14

sin45 * 14 = x

x = 9.899494936611665

6 0

2 years ago