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Fudgin [204]
3 years ago
5

Is anyone good at Simplifying Radical Expressions?

Mathematics
1 answer:
Lynna [10]3 years ago
3 0
All you really have to do is find the prime factorization of the term.  And for every pair of like factors you can move that term outside of the radical sign (for square roots)  If you were doing cube roots you would need to find threesomes of factors... for example..

20^(1/2)

pf 20=2*2*5  so you have two twos so you can simplify to 2(5)^(1/2)

108^(1/3)

pf 108=2*2*3*3*3 so you have 3^3 so you can simplify to 3(4)^(1/3)
You might be interested in
Multiplying mixed numbers and whole numbers 1 1/2 x 2/1 =
Nezavi [6.7K]

Answer: 3

Step-by-step explanation:

1. Convert the mixed number to fraction:

- Multiply the denominator of the fraction by the whole number.

- Add the product obtained and the numerator of the fraction.

- Write the sum obtained as the numerator and rewrite the original denominator of the fraction.

Then:

1\ 1/2=\frac{(1)(2)+1}{2}=\frac{3}{2}

2. Multiply the numerators.

3. Multiply the denominator.

4. Reduce the fraction.

Then:

(\frac{3}{2})(\frac{2}{1})=\frac{6}{2}=3

5 0
3 years ago
What is the outlier in 1117 1465 513 437 1038 954 650 893 456 1018
Elza [17]
Wouldnt it be the out side numbers ?at both ends?
3 0
4 years ago
Can someone help me with this math homework please!
ZanzabumX [31]

Answer:

You can do this on ur own

Step-by-step explanation:

Trust me

4 0
3 years ago
Read 2 more answers
8 5/6 + 2 3/4 +__=14 this is fractions so the answer should be a fraction please help
Mariulka [41]

Answer:

2 5/12

Step-by-step explanation:

8 5/6 + 2 3/4 = 8 10/12 + 2 9/12  =  10 19/12  =  10 + 1 7/12  =  11 7/12

13 12/12 - 11 7/12 = 2 5/12

3 0
3 years ago
Find the 63rd term of the arithmetic sequence -1, 5, 11, ...−1,5,11,...
Ugo [173]

Answer:

a_6_3=371

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference

we have

-1,5,11,...

Let

a_1=-1\\a_2=5\\a_3=11

a_2-a_1=5-(-1)=5+1=6

a_3-a_2=11-5=6

The common difference is d=6

We can write an Arithmetic Sequence as a rule

a_n=a_1+d(n-1)

where

a_n is the nth term                

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have

n=63\\d=6\\a_1=-1

substitute

a_6_3=-1+6(63-1)

a_6_3=-1+6(62)

a_6_3=-1+372

a_6_3=371

6 0
4 years ago
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