Answer:
For numbers between 0.1 and 0.2, there is a 1 in the tenths' place: 0.11, 0.12, 0.13, and so on. For numbers between 0.2 and 0.3, there is a 2 in the tenths' place: 0.21, 0.22, 0.23, and so forth. For example, the number “seven and forty-two hundredths” can be written as 7.42.
Step-by-step explanation:
Ummmmmmmmm that is a mixed number already
That is true because the square root of 32 is about 5.66, so 4.65 IS less than it.
-I5I=-5 vs. I-5I= 5
The absolute value will stay the same for both negative and positive. The result will change depending on where you put your absolute value signs.

Setting

, you have

. Then the integral becomes




Now,

in general. But since we want our substitution

to be invertible, we are tacitly assuming that we're working over a restricted domain. In particular, this means

, which implies that

, or equivalently that

. Over this domain,

, so

.
Long story short, this allows us to go from

to


Computing the remaining integral isn't difficult. Expand the numerator with the Pythagorean identity to get

Then integrate term-by-term to get


Now undo the substitution to get the antiderivative back in terms of

.

and using basic trigonometric properties (e.g. Pythagorean theorem) this reduces to