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USPshnik [31]
3 years ago
12

(15-26)/3 + (-8+19)/2

Mathematics
2 answers:
Gre4nikov [31]3 years ago
7 0

Answer:

11/6

Step-by-step explanation:

(15-26)/3 + (-8+19)/2

Do parentheses:

-11/3 + 11/2

Find the common denominator:

-11(2)/3(2) + 11(3)/2(3)

Multiply:

-22/6 + 33/6

Add the fractions:

11/6

Valentin [98]3 years ago
4 0
Answer is 1.83, with the three repeated.
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The radioactive element americium-241 has a half-life of 432 years. How many years will it take a 10 gram mass of americium-241
geniusboy [140]
<h2>Answer: 816 years</h2>

This problem can be solved using the <u>Radioactive Half Life Formula: </u>

<u />

A=A_{o}.2^{\frac{-t}{h}}   (1)

Where:

A=2.7g is the final amount of the material

A_{o}=10g is the initial amount of the material

t is the time elapsed  (the quantity we are asked to find)

h=432y is the half life of americium-241

Knowing this, let's find t from (1):

2.7g=(10g).2^{\frac{-t}{432y}}  

\frac{2.7g}{10g}=2^{\frac{-t}{432y}}  

0.27g=2^{\frac{-t}{432y}}  

Applying natural logarithm in both sides:

ln(0.27g)=ln(2^{\frac{-t}{432y}})  

-1.309=-\frac{t}{432y}ln(2)  

-t=\frac{(-1.309)(432y)}{0.693}  

<u></u>

<u>Finally:</u>

t=816y

3 0
3 years ago
Which relationship has a zero slope?
Kay [80]
A Horizontal line means you get a slope of zero
7 0
3 years ago
Read 2 more answers
Simplify the expression 9t^2+14-17t+6t-8t^2
slamgirl [31]

Answer:

t^2 - 11t + 14

Step-by-step explanation:

Begin by grouping like terms in 9t^2+14-17t+6t-8t^2.

First we have 9t^2 - 8t^2, or 1t^2.

Next, we have -17t + 6t, or -11t.

Last, we have the constant term 14.

The expression in simplified form is t^2 - 11t + 14.

6 0
3 years ago
HELPPPPPPPPP ASAPPPPPPPP PLSSSS
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-1/3(px-2) = 9

ok! so first we want to isolate x.

multiply both sides by -3/1 (this is the reciprocal of -1/3)

(px-2) = -27

px = -27 + 2

px = -25

x = -25/p

hope this helped!

8 0
3 years ago
Which basic trigonometric identity would you use to verify that tan x cos x =sin x
True [87]

Answer:

\huge\boxed{\tan x=\dfrac{\sin x}{\cos x}}

Step-by-step explanation:

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