For this case we have the following functions:
h (x) = 2x - 5
t (x) = 6x + 4
Part A: (h + t) (x)
(h + t) (x) = h (x) + t (x)
(h + t) (x) = (2x - 5) + (6x + 4)
(h + t) (x) = 8x - 1
Part B: (h ⋅ t) (x)
(h ⋅ t) (x) = h (x) * t (x)
(h ⋅ t) (x) = (2x - 5) * (6x + 4)
(h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
(h ⋅ t) (x) = 12x ^ 2 - 22x - 20
Part C: h [t (x)]
h [t (x)] = 2 (6x + 4) - 5
h [t (x)] = 12x + 8 - 5
h [t (x)] = 12x + 3
Answer:
The slope of the line y = 1 is zero.
Answer:
aₙ= 4n+11
Step-by-step explanation:
the sequence 15, 19, 23, 27
is AP with the first term 15 and
the common difference 19-15=23-19=27-23= 4
aₙ= a₁+(n-1)d
aₙ= 15+(n-1)*4= 15+4n- 4= 4n+11
aₙ= 4n+11
Answer:
c
Step-by-step explanation:
c
fg^3 / g^3f = 1
f^4 / f*f*f*f = f^4 / f^4 = 1
f^2g^3 / f^3g^2 = g/f
f*f/f^2 = f^2 / f^2 = 1
Answer:
f^2g^3 / f^3g^2