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alina1380 [7]
3 years ago
12

Anyone know the answer to this?

Mathematics
2 answers:
zavuch27 [327]3 years ago
6 0

Answer:

3x-5+19-x+2x

5x-x=14

4x=14

Hope that helps

jeyben [28]3 years ago
3 0
3x-5+19-x+2x
5x-x=14
4x=14
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2cos^2x+cosx-1=0<br> Find the degree solutions
Lapatulllka [165]
2cos²x+cos x-1=0

cos x=t

2t²+t-1=0

t=[-1⁺₋√(-1+8)]/2=(-1⁺₋3)/4
We have two possible set solutions:
First set solutions.
t₁=(-1-3)/2=-4/4=-1   
cos x=-1  ⇒x=cos⁻¹ (-1)=π +2kπ    or     180º+360ºk    (k=(...-2,-1,0,1,2...)

Second set solutions:
t₂=(-1+3)/4=2/4=1/2

cos x=1/2  ⇒ x=cos⁻¹ 1/2=π/3+2kπ   U   5π/3+ 2kπ   or
60º+360ºK  U 300º+360ºK        (k=...-2,-1,0,1,2,...)

solutions: first set solutions U second set solutions:

Answer in radians : π +2kπ U π/3+2kπ U 5π/3+ 2kπ   (k=...-1,0,1,...)
Answer is degrees: 180º+360ºk U 60º+360ºK  U 300º+360ºK        (k=...-2,-1,0,1,2,...)
4 0
3 years ago
Write the inequality:There are fewer than 20 days left in October.
Norma-Jean [14]

Answer:

I found the answer on this website. It seems correct! Link Below!

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How do you verify the identity?
rodikova [14]
Their both the answer hope this helps

5 0
3 years ago
(-1,3) (3,0) (-1.-2) find perimiter
KATRIN_1 [288]

Answer:

p≈14.5

Step-by-step explanation:

Find the distance between the three pairs first using the distance formula:

\sqrt{(x2-x1)^2+(y2-y1)^2}

Take the first two points, (-1,3)(3,0) and insert the values:

\sqrt{(3-(-1))^2+(0-3)^2}

Simplify parentheses (two negatives makes a positive):

\sqrt{(3+1)^2+(0-3)^2}\\\\ \sqrt{(4)^2+(-3)^2}\\\\\sqrt{16+9}\\  \\\sqrt{25}=5

The distance between the first two points is 5. Use the nest two points, (3,0)(-1,-2) and insert values:

\sqrt{(-1-3)^2+(-2-0)^2}

Simplify parentheses:

\sqrt{(-4)^2+(-2)^2}\\ \\\sqrt{16+4} \\\\\sqrt{20}=4.5

The distance between the nest two point is about 4.5. Use the remaining two points, (-1,-2)(-1,3) and insert values:

\sqrt{(-1-(-1))^2+(3-(-2))^2}

Simplify parentheses (two negatives makes a positive):

\sqrt{(-1+1)^2+(3+2)^2}\\\\\sqrt{(0)^2+(5)^2}\\ \\\sqrt{0+25}\\ \\\sqrt{25}=5

The distance between the last points is 5. Add the distances together to find the perimeter of the triangle:

5+4.5+5\\10+4.5\\14.5

The perimeter is about 14.5.

4 0
3 years ago
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